SSC CGL 13 September 2025 · Shift 2 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 17 of 192
13 September 2025 · Shift 2
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
In the following question, select the related word from the given alternatives.
Chef : Food :: Architect : ?
A.Cook
B.Serve
C.Recipe
D.Design
Solution
Word analogy
A chef creates food — that is his professional output.
An architect creates designs of buildings.
Hence Design — option (d).
2
In the following question, select the related word from the given alternatives.
Deontology : Duty :: Utilitarianism : ?
A.Pleasure
B.Consequence
C.Benefit
D.Outcome
Solution
Word analogy — ethics
Deontology judges actions by duty — duty is its central criterion.
Utilitarianism judges actions by their consequences (the greatest good).
Hence Consequence — option (b).
3
Select the letters from among the given options that can replace the question mark (?) in the following series.
I, K, ?, O, Q, ?, U, W
A.Q, X
B.M, S
C.P, W
D.R, W
Solution
Letter series (+2)
The series moves +2 each time: I, K, M, O, Q, S, U, W.
The first blank is K + 2 = M and the second is Q + 2 = S.
Hence M, S — option (b).
4
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
STU, VWX, YZA, ?
A.BZD
B.ACD
C.BCD
D.BCR
Solution
Letter series (+3 clusters)
Each cluster contains three consecutive letters.
After YZA the next three consecutive letters (cyclic) are B, C, D.
Hence BCD — option (c).
5
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
VJT, SGQ, PDN, MAK, ?
A.JHX
B.JXG
C.KXH
D.JXH
Solution
Letter series (−3 each)
Every letter moves −3 (cyclic) from term to term.
M − 3 = J, A − 3 = X, K − 3 = H.
Hence JXH — option (d).
6
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:
RGOW, RLYL, RQIA, RVSP, ?
A.RACE
B.RABF
C.RBCE
D.RACF
Solution
Letter series (+5, +10, +15)
The 1st letter R is constant; the 2nd letters move +5 (G, L, Q, V → A).
The 3rd letters move +10 (O, Y, I, S → C) and the 4th letters move +15 (W, L, A, P → E), all cyclic.
Hence RACE — option (a).
7
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:
CKSA, CRGV, CYUQ, CFIL, ?
A.CNYH
B.CNWG
C.CMXG
D.CMWG
Solution
Letter series (+7, +14, −5)
C is constant; the 2nd letters move +7 (K, R, Y, F → M).
The 3rd letters move +14 (S, G, U, I → W) and the 4th letters move −5 (A, V, Q, L → G), all cyclic.
Hence CMWG — option (d).
8
Complete the pattern:
96, 76.8, 61.44, 49.152, ?
A.40.321
B.38.271
C.37.332
D.39.321
Solution
Series (×0.8)
Each term is 80% of the previous one (×0.8).
49.152 × 0.8 = 39.3216.
≈ 39.321 — option (d).
9
Each of the letters in the word CONTRAST is arranged in alphabetical order. How many letters are there in the English alphabetical series between the letter that is first from the right and the one that is fifth from the left in the new letter-cluster formed?
A.2
B.3
C.1
D.5
Solution
Alphabetical arrangement — CONTRAST
CONTRAST arranged alphabetically: A, C, N, O, R, S, T, T.
First from the right = T; fifth from the left = R.
Between R and T lies only S — 1 letter; option (c).
10
Which of the following addresses are identical to each other:
1. K. Iyer 16-D Beach Residency, Thiruvananthapuram, 695013
2. K. lyer 16-D Beach Residency, Thiruvananthapuram, 695012
3. K. lyer 16-D Beach Residency, Thiruvananthapuram, 695014
4. K. lyer 16-D Beach Residency, Thiruvananthapuram, 695014
A.3 and 4
B.1 and 4
C.2 and 4
D.1 and 3
Solution
Address matching
Addresses 1, 2 and 3 differ in spelling (Iyer/lyer) or PIN code (695013 / 695012 / 695014).
Addresses 3 and 4 match character-for-character, including PIN 695014.
Hence 3 and 4 — option (a).
11
Which of the following is/are identical to the address given:
Sandeep Kumar 31/6, Ashok Vihar, Gurugram, 122002
1. Sandeep Kumar 21/6, Ashok Vihar, Gurugram, 122002
2. Sandeep Kumar 31/9, Ashok Vihar, Gurugram, 122004
3. Sandeep Kumar 41/6, Ashok Vihar, Gurugram, 122005
4. Sandeep Kumar 31/6, Ashok Vihar, Gurugram, 122002
A.1 Only
B.3 Only
C.4 Only
D.2 Only
Solution
Address matching
Addresses 1, 2 and 3 change the house number or PIN code (21/6, 31/9, 41/6).
Only address 4 matches the given address exactly — 31/6, Ashok Vihar, 122002.
Hence 4 Only — option (c).
12
Find the best option that best completes the analogy.
GIH : ILL :: CAB : ?
A.EDG
B.FEF
C.EDF
D.EEG
Solution
Letter analogy (+2, +3, +4)
GIH → ILL: the letters move +2, +3, +4 respectively.
Apply to CAB: C + 2 = E, A + 3 = D, B + 4 = F.
Hence EDF — option (c).
13
Find the option that best completes the analogy.
EN : YX :: DP : ?
A.YZ
B.YA
C.XA
D.XZ
Solution
Letter analogy (+20, +10)
E + 20 = Y and N + 10 = X (both cyclic).
Apply to DP: D + 20 = X and P + 10 = Z.
Hence XZ — option (d).
14
Ten persons are sitting in two parallel rows containing five persons each, such that there is an equal distance between adjacent persons.
Line 1: Five men (P–T) are seated and all of them are facing South.
Line 2: Five women (X–B) are seated and all of them are facing North.
Based on the arrangement, answer the question:
S is opposite to X. X is at one of the extreme ends of Line 2. Y is at the center position of Line 2.
Who is second to the right of X in Line 2 (facing North)?
A.Y
B.Z
C.B
D.A
Solution
Two parallel rows
X sits at an extreme end of Line 2 and Y sits at the centre (3rd seat).
Whichever end X occupies, moving two seats towards her right always lands on the centre seat.
The centre seat is Y — option (a).
15
In each of the following questions, a specific rearrangement pattern is applied to the first word to form the second. Identify the same pattern and apply it to the third word to determine the correct answer from the given alternatives.
GROUND : RGUODN :: AROUND : ?
A.RAUODN
B.ARUODN
C.RAOUND
D.ROUNDA
Solution
Pair swapping
GROUND → RGUODN: each pair of letters is swapped — (GR)(OU)(ND) → (RG)(UO)(DN).
AROUND: (AR)(OU)(ND) → (RA)(UO)(DN).
Hence RAUODN — option (a).
16
In each of the following questions, the second group of letters is formed from the first using a specific alphabetical transformation. Apply the same pattern to the third group and find the correct option that completes the Analogy.
UIOZ : WKPA :: QDXM : ?
A.SFNY
B.SNYF
C.RSEF
D.SFYN
Solution
Letter analogy (+2, +2, +1, +1)
UIOZ → WKPA: the letters move +2, +2, +1, +1 respectively (cyclic).
QDXM: Q+2 = S, D+2 = F, X+1 = Y, M+1 = N.
Hence SFYN — option (d).
17
Choose the odd one:
A.3, 9, 27
B.5, 25, 125
C.2, 4, 8
D.6, 36, 64
Solution
Odd one out (n, n², n³)
In the other sets the pattern is n, n², n³: (3, 9, 27), (5, 25, 125), (2, 4, 8).
In (6, 36, 64): 6³ = 216, not 64.
Hence option (d).
18
In each of the following questions, a group of three numbers/symbols is given in each option. Identify the group that does NOT follow the same pattern as the others.
A.A1 : X24 : D4
B.G7 : M13 : J10
C.W23 : T20 : Z26
D.E6 : B4 : H8
Solution
Letter–number pairing
In options (a), (b) and (c) every number equals the alphabetical position of its letter (A=1, X=24, G=7, W=23 …).
In option (d), E is the 5th letter but is paired with 6 (B4 and H8 are correct).
Hence option (d) breaks the pattern.
19
In each of the following questions, a group of three numbers/symbols is given in each option. Identify the group that does NOT follow the same pattern as the others.
A.Q6S : P7# : O8@
B.T2% : S3! : R4&
C.W1* : V2( : U3)
D.Z5$ : Y6$ : X7$
Solution
Symbol-group pattern
In (a), (b) and (c) the letters step back, the numbers rise by 1, and the three symbols are all DIFFERENT.
In (d) the same symbol $ is repeated in all three members.
Hence option (d) breaks the pattern.
20
P is the daughter of Q. R is the husband of P. S is the son of R. How is Q related to S?
A.Grandfather
B.Father
C.Cannot be determined
D.Grandmother
Solution
Blood relation — gender unknown
S is the son of R and P, so Q (P’s parent) is S’s grandparent.
But the gender of Q is not given — Q may be the grandfather or the grandmother.
Hence Cannot be determined — option (c).
21
If 'X' means '+', 'Y' means '−', 'Z' means '×', and 'W' means '÷', what is the value of the following expression?
30 W 6 X 4 Z 8 Y 4 = ?
P's father's wife's only daughter is Q. How is P related to Q?
A.Sibling
B.Uncle
C.Nephew
D.Cousin
Solution
Blood relation
P's father's wife is P's mother; her only daughter is Q.
So Q is P’s sister, making P her brother (or sister).
The relation is Sibling — option (a).
23
Introducing a boy, a girl says, "He is the son of my father's only son." Who is the boy to the girl?
A.Brother
B.Son
C.Nephew
D.Cousin
Solution
Blood relation
The girl's father's only son is the girl's brother.
The boy is that brother’s son.
Hence the boy is the girl’s Nephew — option (c).
24
P is the wife of Q. Q is the brother of R. R is the father of S. How is P related to S?
A.Mother
B.Aunt
C.Grandmother
D.Sister-in-law
Solution
Blood relation
S is the child of R, and Q is R’s brother — so Q is S’s uncle.
P, being Q’s wife, is the uncle’s wife.
Hence P is S’s Aunt — option (b).
25
If '+' means '−', '−' means '+', '×' means '÷', then 100 + 20 − 10 × 10 = ?
The series moves +2 each time: I, K, M, O, Q, S, U, W.
The first blank is K + 2 = M and the second is Q + 2 = S.
Hence M, S — option (b).
Each cluster contains three consecutive letters.
After YZA the next three consecutive letters (cyclic) are B, C, D.
Hence BCD — option (c).
Every letter moves −3 (cyclic) from term to term.
M − 3 = J, A − 3 = X, K − 3 = H.
Hence JXH — option (d).
The 1st letter R is constant; the 2nd letters move +5 (G, L, Q, V → A).
The 3rd letters move +10 (O, Y, I, S → C) and the 4th letters move +15 (W, L, A, P → E), all cyclic.
Hence RACE — option (a).
C is constant; the 2nd letters move +7 (K, R, Y, F → M).
The 3rd letters move +14 (S, G, U, I → W) and the 4th letters move −5 (A, V, Q, L → G), all cyclic.
Hence CMWG — option (d).
Each term is 80% of the previous one (×0.8).
49.152 × 0.8 = 39.3216.
≈ 39.321 — option (d).
CONTRAST arranged alphabetically: A, C, N, O, R, S, T, T.
First from the right = T; fifth from the left = R.
Between R and T lies only S — 1 letter; option (c).
GIH → ILL: the letters move +2, +3, +4 respectively.
Apply to CAB: C + 2 = E, A + 3 = D, B + 4 = F.
Hence EDF — option (c).
E + 20 = Y and N + 10 = X (both cyclic).
Apply to DP: D + 20 = X and P + 10 = Z.
Hence XZ — option (d).
X sits at an extreme end of Line 2 and Y sits at the centre (3rd seat).
Whichever end X occupies, moving two seats towards her right always lands on the centre seat.
The centre seat is Y — option (a).
GROUND → RGUODN: each pair of letters is swapped — (GR)(OU)(ND) → (RG)(UO)(DN).
AROUND: (AR)(OU)(ND) → (RA)(UO)(DN).
Hence RAUODN — option (a).
UIOZ → WKPA: the letters move +2, +2, +1, +1 respectively (cyclic).
QDXM: Q+2 = S, D+2 = F, X+1 = Y, M+1 = N.
Hence SFYN — option (d).
In the other sets the pattern is n, n², n³: (3, 9, 27), (5, 25, 125), (2, 4, 8).
In (6, 36, 64): 6³ = 216, not 64.
Hence option (d).
In options (a), (b) and (c) every number equals the alphabetical position of its letter (A=1, X=24, G=7, W=23 …).
In option (d), E is the 5th letter but is paired with 6 (B4 and H8 are correct).
Hence option (d) breaks the pattern.
S is the son of R and P, so Q (P’s parent) is S’s grandparent.
But the gender of Q is not given — Q may be the grandfather or the grandmother.
Hence Cannot be determined — option (c).
P's father's wife is P's mother; her only daughter is Q.
So Q is P’s sister, making P her brother (or sister).
The relation is Sibling — option (a).
The girl's father's only son is the girl's brother.
The boy is that brother’s son.
Hence the boy is the girl’s Nephew — option (c).
S is the child of R, and Q is R’s brother — so Q is S’s uncle.
P, being Q’s wife, is the uncle’s wife.
Hence P is S’s Aunt — option (b).