SSC CGL 15 September 2025 · Shift 3 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 45 of 192
15 September 2025 · Shift 3
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
In the following question, select the related word from the given alternatives.
Fuel : Engine :: Mercury : ?
A.Thermometer
B.Power
C.Engine
D.Oil
Solution
Analogy — substance : device
Relationship: substance : device in which it is used.
Fuel is used inside an engine.
Mercury is the substance used inside a thermometer.
Hence option (a).
2
In the following question, select the related word from the given alternatives.
Governance : Legitimacy :: Justice : ?
A.Democracy
B.Equity
C.Injustice
D.Efficiency
Solution
Analogy — concept : ideal
Relationship: an idea and the core value that gives it worth.
Governance derives its worth from legitimacy.
Justice derives its worth from equity (fairness).
Hence option (b).
3
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
DAG, FCI, HEK, JGM, ?
A.WUG
B.YOI
C.LIO
D.HEK
Solution
Letter series (+2)
Every letter of a cluster moves +2 in the next cluster.
1st letters: D, F, H, J → L; 2nd letters: A, C, E, G → I.
3rd letters: G, I, K, M → O.
Hence LIO — option (c).
4
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
RST, ?, XYZ, ABC
A.UVW
B.UBD
C.USD
D.ABG
Solution
Consecutive triplets
Each cluster has three consecutive letters, and clusters jump +3.
After RST the next set of three consecutive letters is U, V, W.
Then comes XYZ, followed by ABC (cyclic) ✓.
Hence UVW — option (a).
5
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
MNQ, OPS, QRU, ?
A.RST
B.STP
C.TUV
D.STW
Solution
Letter series (+2)
All three positions move +2 each time.
1st: M, O, Q → S; 2nd: N, P, R → T.
3rd: Q, S, U → W.
Hence STW — option (d).
6
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:
ACHJ, AGPV, ?, AOFT, ASNF
A.AKXH
B.AKPH
C.AKOH
D.AKMH
Solution
Letter series (+4, +8, +12)
The 1st letter A is constant throughout.
2nd letters move +4 (C, G, K, O, S); 3rd letters move +8 (H, P, X, F, N — cyclic).
4th letters move +12 (J, V, H, T, F — cyclic).
So the missing cluster is AKXH — option (a).
7
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:
ZDFH, ZFJN, ZHNT, ZJRZ, ?
A.ZNJH
B.ZGFD
C.ZLVF
D.ZFDS
Solution
Letter series (+2, +4, +6)
Z stays fixed at position 1.
2nd letters +2 (D, F, H, J → L); 3rd letters +4 (F, J, N, R → V).
4th letters +6 (H, N, T, Z → F, cyclic).
Hence ZLVF — option (c).
8
Complete the series: 42, 59, 79, 102, 128, ?
A.158
B.128
C.167
D.157
Solution
Series — rising differences
Differences: 59−42 = 17, 79−59 = 20, 102−79 = 23, 128−102 = 26.
They rise by 3 each time, so the next difference is 29.
128 + 29 = 157.
Hence option (d).
9
Each of the letters in the word FRIEND is arranged in alphabetical order. How many letters are there in the English alphabetical series between the letter that is second from the left and the one that is third from the right in the new letter-cluster formed?
A.Two
B.Four
C.Three
D.Five
Solution
Alphabetical arrangement — FRIEND
FRIEND sorted: D, E, F, I, N, R.
Second from the left = E; third from the right = I.
Between E and I lie F, G, H.
Count = three — option (c).
10
Which of the following is/are identical to the address given:
Amit Yadav 18B, Maple Heights, Sector 49, Gurugram, 122016
1. Amit Yadav 18B, Maple Heights, Sector 45, Gurgaon, 122018
2. Amit Yadav 18B, Maple Heights, Sector 49, Gurugram, 122016
3. Amit Yadav 19B, Maple Heights, Sector 45, Gurgaon, 122003
4. Amit Yadav 18B, Maple Heights, Sector 49, Gurugram, 122016
A.1 and 4
B.1 and 3
C.2 and 4
D.3 and 4
Solution
Address matching
Set 1 changes the sector (45), the city (Gurgaon) and the PIN (122018).
Set 3 changes the house number (19B) as well as sector and PIN.
Sets 2 and 4 match the given address character for character.
Hence 2 and 4 — option (c).
11
Which of the following is/are identical to the address given:
Manish Singh 10/3, Crystal Park, Faridabad, 121003
1. Manish Singh 10/3, Crystal Park, Faridabad, 121003
2. Manish Singh 10/3, Crystal Park, Faridabad, 121003
3. Manish Singh 10-3, Crystal Park, Faridabad, 121002
4. Manish Singh 10/3, Crystal Park, Faridabad, 121001
A.1 and 2
B.2 and 3
C.1 and 4
D.3 and 4
Solution
Address matching
Set 3 writes 10-3 with a hyphen and changes the PIN to 121002.
Set 4 changes the PIN to 121001.
Sets 1 and 2 are exactly identical, including PIN 121003.
Hence 1 and 2 — option (a).
12
Find the group of letters that best completes the analogy based on the given letter transformation pattern.
STONE : TUTOF :: PAPER : ?
A.QBUFS
B.QVHRJ
C.UTONI
D.IPFHR
Solution
Coding (+1, +1, +5, +1, +1)
STONE → TUTOF: S+1 = T, T+1 = U, O+5 = T, N+1 = O, E+1 = F.
So the shifts by position are +1, +1, +5, +1, +1.
PAPER: P+1 = Q, A+1 = B, P+5 = U, E+1 = F, R+1 = S.
Hence QBUFS — option (a).
13
In the following question, a pair of letters is given, followed by its corresponding product of alphabetical positions (A=1, B=2, …, Z=26). A second pair of letters is given without its product. Identify the correct product for the second pair that maintains the same relationship as the first.
Z × L : 26 × 12 :: T × A : ?
A.22 × 24
B.21 × 23
C.20 × 1
D.20 × 26
Solution
Place-value products
Each letter is replaced by its alphabetical place value.
Z = 26 and L = 12, giving 26 × 12 ✓.
T is the 20th letter and A is the 1st.
So T × A = 20 × 1 — option (c).
14
In a row of 70 students, Mahi is 25th from the left and Nisha is 20th from the right. How many students are there between them?
A.26
B.25
C.28
D.24
Solution
Row — students between
Bring both to the same side: Mahi's position from the right = 70 − 25 + 1 = 46.
Nisha is 20th from the right.
Students between them = 46 − 20 − 1.
= 25 — option (b).
15
In each of the following questions, the second word is formed by rearranging the letters of the first word according to a specific pattern. Identify the same rearrangement rule and apply it to the third word to select the correct answer from the given alternatives.
OUTPUT : TUOTUP :: EIGHTY : ?
A.GIEYTH
B.GIEYHT
C.GIYETH
D.GIETYH
Solution
Letter rearrangement (1↔3, 4↔6)
OUTPUT → TUOTUP: the 1st and 3rd letters swap (O↔T) and the 4th and 6th swap (P↔T); 2nd and 5th stay.
Apply to EIGHTY (E I G H T Y): swap E↔G and H↔Y.
Result: G I E Y T H.
Hence GIEYTH — option (a).
16
In each of the following questions, the second word is formed by rearranging the letters of the first word according to a specific pattern. Identify the same rearrangement rule and apply it to the third word to choose the correct answer from the given alternatives.
HUNGRY : UHNGYR :: NATION : ?
A.ANTION
B.ANTINO
C.ANITNO
D.AINTNO
Solution
Pair swapping (1-2, 5-6)
HUNGRY → UHNGYR: the first pair swaps (HU → UH) and the last pair swaps (RY → YR); the middle pair NG stays.
Apply to NATION: (NA)(TI)(ON).
Swap the outer pairs: (AN)(TI)(NO).
Hence ANTINO — option (b).
17
A introduces B as the son of the only brother of her mother's husband. How is B related to A?
A.Cousin
B.Brother
C.Uncle
D.Nephew
Solution
Blood relation
A's mother's husband is A's father.
The only brother of A's father is A's uncle.
B, being that uncle’s son, is A’s cousin.
Hence option (a).
18
What comes next in the series: 4, 8, 14, 22, 32, ?
A.40
B.42
C.44
D.46
Solution
Series — even differences
Differences: 4, 6, 8, 10 — rising by 2 each time.
The next difference is 12.
32 + 12 = 44.
Hence option (c).
19
In each of the following questions, a group of three numbers/symbols is given in each option. Identify the group that does NOT follow the same pattern as the others.
A.P16 : O15 : K11
B.N14 : J10 : H8
C.L12 : N14 : P17
D.Q17 : O15 : L12
Solution
Letter–place value groups
In each group the number should equal the alphabetical place value of its letter.
(a) P=16 ✓, O=15 ✓, K=11 ✓; (b) N=14, J=10, H=8 ✓; (d) Q=17, O=15, L=12 ✓.
In (c) L=12 ✓ and N=14 ✓, but P = 16, not 17 ✗.
Hence option (c).
20
In each of the following questions, a group of three numbers/symbols is given in each option. Identify the group that does NOT follow the same pattern as the others.
A.B3@ : E6# : I10$
B.C4% : G8^ : F7&
C.C4* : E6( : G8)
D.D5_ : G8@ : J13$
Solution
Letter + next place value
In each pair the number is one MORE than the letter’s place value.
(a) B=2→3, E=5→6, I=9→10 ✓; (b) C=3→4, G=7→8, F=6→7 ✓; (c) C=3→4, E=5→6, G=7→8 ✓.
(d) D=4→5 ✓, G=7→8 ✓, but J=10 should give 11, not 13 ✗.
Hence option (d).
21
Which group doesn't match the pattern?
A.10, 20, 40
B.15, 20, 35
C.20, 32, 56
D.14, 28, 56
Solution
Number triples
Rule: the first gap is HALF of the second gap.
(a) 10 and 20 ✓; (c) 12 and 24 ✓; (d) 14 and 28 ✓.
(b) gaps are 5 and 15 — 5 is one-third, not half ✗.
Hence option (b).
22
Introducing a woman, a man says, "She is the daughter of my only brother's wife." How is the woman related to that man?
A.Cousin
B.Grandson
C.niece
D.Son
Solution
Blood relation
The man's only brother's wife is his sister-in-law.
Her daughter is therefore his brother’s daughter.
A brother’s daughter is one’s niece.
Hence option (c).
23
Given:
A & B : A is the husband of B
A % B : A is the daughter of B
A # B : A is the father of B
A @ B : A is the brother of B
What does A # B & C mean?
A.A is the father of C
B.A is the brother of C
C.A is the father-in-law of C
D.A is the husband of C
Solution
Coded relations
Break it up: A # B means A is the father of B.
B & C means B is the husband of C.
So A is the father of C’s husband — that is, C’s father-in-law.
Hence option (c).
24
Looking at a woman, a man said, "Her mother is the only daughter of my mother." How is that woman related to the man?
A.Brother
B.Niece
C.Son
D.Cousin
Solution
Blood relation
The only daughter of the man's mother is his own sister.
So the woman’s mother is the man’s sister.
The daughter of one’s sister is a niece.
Hence option (b).
25
If '+' = '×', '×' = '+', '−' = '÷'; then 5 + 6 × 6 − 2 = ?
Every letter of a cluster moves +2 in the next cluster.
1st letters: D, F, H, J → L; 2nd letters: A, C, E, G → I.
3rd letters: G, I, K, M → O.
Hence LIO — option (c).
Each cluster has three consecutive letters, and clusters jump +3.
After RST the next set of three consecutive letters is U, V, W.
Then comes XYZ, followed by ABC (cyclic) ✓.
Hence UVW — option (a).
All three positions move +2 each time.
1st: M, O, Q → S; 2nd: N, P, R → T.
3rd: Q, S, U → W.
Hence STW — option (d).
The 1st letter A is constant throughout.
2nd letters move +4 (C, G, K, O, S); 3rd letters move +8 (H, P, X, F, N — cyclic).
4th letters move +12 (J, V, H, T, F — cyclic).
So the missing cluster is AKXH — option (a).
Z stays fixed at position 1.
2nd letters +2 (D, F, H, J → L); 3rd letters +4 (F, J, N, R → V).
4th letters +6 (H, N, T, Z → F, cyclic).
Hence ZLVF — option (c).
Differences: 59−42 = 17, 79−59 = 20, 102−79 = 23, 128−102 = 26.
They rise by 3 each time, so the next difference is 29.
128 + 29 = 157.
Hence option (d).
FRIEND sorted: D, E, F, I, N, R.
Second from the left = E; third from the right = I.
Between E and I lie F, G, H.
Count = three — option (c).
STONE → TUTOF: S+1 = T, T+1 = U, O+5 = T, N+1 = O, E+1 = F.
So the shifts by position are +1, +1, +5, +1, +1.
PAPER: P+1 = Q, A+1 = B, P+5 = U, E+1 = F, R+1 = S.
Hence QBUFS — option (a).
Each letter is replaced by its alphabetical place value.
Z = 26 and L = 12, giving 26 × 12 ✓.
T is the 20th letter and A is the 1st.
So T × A = 20 × 1 — option (c).
Bring both to the same side: Mahi's position from the right = 70 − 25 + 1 = 46.
Nisha is 20th from the right.
Students between them = 46 − 20 − 1.
= 25 — option (b).
OUTPUT → TUOTUP: the 1st and 3rd letters swap (O↔T) and the 4th and 6th swap (P↔T); 2nd and 5th stay.
Apply to EIGHTY (E I G H T Y): swap E↔G and H↔Y.
Result: G I E Y T H.
Hence GIEYTH — option (a).
HUNGRY → UHNGYR: the first pair swaps (HU → UH) and the last pair swaps (RY → YR); the middle pair NG stays.
Apply to NATION: (NA)(TI)(ON).
Swap the outer pairs: (AN)(TI)(NO).
Hence ANTINO — option (b).
A's mother's husband is A's father.
The only brother of A's father is A's uncle.
B, being that uncle’s son, is A’s cousin.
Hence option (a).
Differences: 4, 6, 8, 10 — rising by 2 each time.
The next difference is 12.
32 + 12 = 44.
Hence option (c).
In each group the number should equal the alphabetical place value of its letter.
(a) P=16 ✓, O=15 ✓, K=11 ✓; (b) N=14, J=10, H=8 ✓; (d) Q=17, O=15, L=12 ✓.
In (c) L=12 ✓ and N=14 ✓, but P = 16, not 17 ✗.
Hence option (c).
In each pair the number is one MORE than the letter’s place value.
(a) B=2→3, E=5→6, I=9→10 ✓; (b) C=3→4, G=7→8, F=6→7 ✓; (c) C=3→4, E=5→6, G=7→8 ✓.
(d) D=4→5 ✓, G=7→8 ✓, but J=10 should give 11, not 13 ✗.
Hence option (d).
Rule: the first gap is HALF of the second gap.
(a) 10 and 20 ✓; (c) 12 and 24 ✓; (d) 14 and 28 ✓.
(b) gaps are 5 and 15 — 5 is one-third, not half ✗.
Hence option (b).
The man's only brother's wife is his sister-in-law.
Her daughter is therefore his brother’s daughter.
A brother’s daughter is one’s niece.
Hence option (c).
Break it up: A # B means A is the father of B.
B & C means B is the husband of C.
So A is the father of C’s husband — that is, C’s father-in-law.
Hence option (c).
The only daughter of the man's mother is his own sister.
So the woman’s mother is the man’s sister.
The daughter of one’s sister is a niece.
Hence option (b).