SSC CGL 19 September 2025 · Shift 1 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 85 of 192
19 September 2025 · Shift 1
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
HKO, MPT, RUY, ?
A.RAS
B.RYS
C.TSG
D.WZD
Solution
Letter series (+5)
Every letter of a cluster moves +5 in the next cluster.
1st letters: H, M, R → W; 2nd letters: K, P, U → Z.
3rd letters: O, T, Y → D (cyclic).
Hence WZD — option (d).
2
Choose the address that is the same as the one given below.
Jantar Mantar, Gangori Bazaar, Near City Palace, Jaipur, Rajasthan - 302002
D.Jantar Mantar, Gangori Bazaar, Near City Palace, Jaipur, Rajasthan - 302002
Solution
Address matching
Options (a), (b) and (c) give an entirely different address (S-50, Gokul Dham) with different states.
Only option (d) repeats the Jantar Mantar address exactly.
Even the PIN 302002 matches only in (d).
Hence option (d).
3
Choose the address that is the same as the one given below.
Sample Address: 27, Black Orchid Complex, S.G. Highway, Ahmedabad, Gujarat - 380054
A.27, Black Orchid Complex, S.G. Highway, Ahmedabad, Gujarat - 380054
B.27 Black Orchid Complex, SG Highway, Ahmedabad, Gujarat - 380054
C.27, Black Orchid Complex, SG. Highway, Ahmedabad, Gujarat - 380054
D.27, Black Orchid Complex, S.G Highway, Ahmadabad, Gujarat - 380054
Solution
Address matching
(b) drops the comma after 27 and the dots in S.G.; (c) writes SG. with one dot.
(d) drops a dot and misspells 'Ahmadabad'.
Only (a) matches the sample punctuation for punctuation.
Hence option (a).
4
Consider the following statement and choose the option that follows.Statement: In recent years, the number of cyclists in cities has increased.
Conclusions:
I. People are becoming environmentally conscious.
II. Car sales have stopped in cities.
A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Statement — conclusions
More cycling suggests a growing preference for clean, non-polluting transport — I follows.
II says car sales have STOPPED, an extreme claim that cycling numbers cannot support.
Both habits can grow side by side.
Hence Only I — option (a).
5
Consider the following statements and choose the option that follows.Statements:
I. The government launched a road safety campaign.
II. The number of accidents on the roads has increased.
A.I is the cause and II is the effect.
B.II is the cause and I is the effect.
C.Both are effects of the same cause.
D.No relation.
Solution
Cause and effect
Accidents rise first, and that prompts the government to act.
Launching a safety campaign is the response to the rise.
So II is the cause and I is the effect.
Hence option (b).
6
Find out the WRONG number in the given series.
346, 256, 176, 104, 46, −4
A.104
B.176
C.346
D.46
Solution
Wrong term in series
Differences: 346 − 256 = 90, 256 − 176 = 80, so the gaps should fall by 10 each time: 90, 80, 70, 60, 50.
176 − 70 = 106, but the series shows 104.
Continuing correctly: 106 − 60 = 46 ✓ and 46 − 50 = −4 ✓.
So 104 is the wrong number — option (a).
7
Read the given statement and conclusions carefully. Decide which of the given conclusions is/are definitely TRUE from the statement.Statement: A > B = C ≤ D < E ≥ F
Conclusions:
I. B < E
II. F > C
A.Only Conclusion I is True.
B.Only Conclusion II is True.
C.Both Conclusion I and Conclusion II are True.
D.Both Conclusion I and Conclusion II are False.
Solution
Coded inequality
B = C ≤ D < E is a single chain in one direction, so B < E is definite — I is true.
For II: C ≤ D < E ≥ F — the signs around E oppose, so C and F cannot be compared.
Hence II is not definite.
Only I — option (a).
8
Which two signs should be interchanged to make the given equation CORRECT?
92 × 23 − 18 + 9 ÷ 3 = 13
A.× and +
B.× and ÷
C.÷ and −
D.+ and −
Solution
Interchange signs
Interchange × and ÷ : the equation becomes 92 ÷ 23 − 18 + 9 × 3.
BODMAS: 92 ÷ 23 = 4 and 9 × 3 = 27.
4 − 18 + 27 = 13 ✓ — it matches the right-hand side.
Hence × and ÷ — option (b).
9
If "+" means subtraction, "−" means division, "×" means addition, and "÷" means multiplication, then find:
16 ÷ 16 − 32 + 3 × 10 = ?
X is the only daughter of W, who is the only son of R. How is X related to R?
A.Daughter
B.Sister
C.Granddaughter
D.Cousin
Solution
Blood relation
W is R’s son, so W belongs to the generation below R.
X is W’s daughter — one more generation down.
So X is R’s granddaughter.
Hence option (c).
11
In the following question, find out the alternative that will replace the question mark.
RBAT : TBAR :: MNPE : ?
A.PMEN
B.ENPM
C.NPEM
D.PENM
Solution
Letter rearrangement
Compare RBAT with TBAR: the FIRST and LAST letters swap (R ↔ T) while the middle pair B, A stays put.
Apply the same to MNPE: swap M and E.
That gives E, N, P, M.
Hence ENPM — option (b).
Read the following statement carefully and identify the conclusion that follows.Statement: The sale of electric vehicles is rapidly increasing in the city.
Conclusions:
I. People want to reduce pollution.
II. Petrol vehicles have now been completely stopped.
A.Only Conclusion I follows
B.Only Conclusion II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Statement — conclusions
Buying electric vehicles points to a wish for cleaner transport — I follows.
II claims petrol vehicles have COMPLETELY stopped, which rising EV sales do not prove.
So only the first conclusion holds.
Hence option (a).
14
Read the following statement carefully and identify the conclusion that follows.Statement: The use of plastic bags has been banned in many cities.
Conclusions:
I. Plastic harms the environment.
II. People will not use any bags now.
A.Only Conclusion I follows
B.Only Conclusion II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Statement — conclusions
A ban is imposed precisely because plastic damages the environment — I follows.
People will simply switch to cloth or paper bags; II is an extreme claim.
So only the first conclusion holds.
Hence option (a).
15
If "QNLD" is coded as "URPH", what is the code for "FQDDBD"?
A.JUHHFH
B.JUHHFG
C.UJHHFH
D.JUHFHH
Solution
Coding (+4)
Q+4 = U, N+4 = R, L+4 = P, D+4 = H — every letter moves +4.
Apply to FQDDBD: F+4 = J, Q+4 = U, D+4 = H.
D+4 = H, B+4 = F, D+4 = H.
Hence JUHHFH — option (a).
16
What comes next?
BY, KR, TK, ?
A.BA
B.CD
C.ZC
D.YC
Solution
Letter series (+9, −7)
1st letters: B(2), K(11), T(20) — each +9 ⇒ next is 29 − 26 = 3 = C.
2nd letters: Y(25), R(18), K(11) — each −7 ⇒ next is 4 = D.
So the pair is C and D.
Hence CD — option (b).
17
Find the odd one out from the given alternatives:
A.Shershah Suri
B.Babar
C.Akbar
D.Humayun
Solution
Mughal rulers
Babar, Akbar and Humayun were rulers of the MUGHAL dynasty.
Shershah Suri founded the Sur dynasty and ruled after defeating Humayun.
So he belongs to a different line.
Hence option (a).
18
If FNZK is coded as GOAL, what is the code for EZHK?
A.FAIL
B.ILFA
C.FBIL
D.GAFB
Solution
Coding (+1)
F+1 = G, N+1 = O, Z+1 = A (cyclic), K+1 = L — every letter moves +1.
Apply to EZHK: E+1 = F, Z+1 = A.
H+1 = I, K+1 = L.
Hence FAIL — option (a).
19
X invested ₹50,000 for 8 months and Y invested ₹40,000 for 12 months. The total profit is ₹33,000. What is X's share?
The series given below contains a sequence of numbers. Accordingly identify the incorrect combination.
9, 36, 144, 578, 2304, 9218
A.36, 578
B.2304, 9218
C.144, 578
D.578, 9218
Solution
Wrong terms in series
Each term should be four times the previous: 9, 36, 144, 576, 2304, 9216.
The series shows 578 in place of 576 and 9218 in place of 9216.
So both those terms break the ×4 rule.
578 and 9218 — option (d).
Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
Every letter of a cluster moves +5 in the next cluster.
1st letters: H, M, R → W; 2nd letters: K, P, U → Z.
3rd letters: O, T, Y → D (cyclic).
Hence WZD — option (d).
Differences: 346 − 256 = 90, 256 − 176 = 80, so the gaps should fall by 10 each time: 90, 80, 70, 60, 50.
176 − 70 = 106, but the series shows 104.
Continuing correctly: 106 − 60 = 46 ✓ and 46 − 50 = −4 ✓.
So 104 is the wrong number — option (a).
B = C ≤ D < E is a single chain in one direction, so B < E is definite — I is true.
For II: C ≤ D < E ≥ F — the signs around E oppose, so C and F cannot be compared.
Hence II is not definite.
Only I — option (a).
Interchange × and ÷ : the equation becomes 92 ÷ 23 − 18 + 9 × 3.
BODMAS: 92 ÷ 23 = 4 and 9 × 3 = 27.
4 − 18 + 27 = 13 ✓ — it matches the right-hand side.
Hence × and ÷ — option (b).
Replace the symbols: 16 × 16 ÷ 32 − 3 + 10.
BODMAS: 16 × = 8.
8 − 3 + 10.
= 15 — option (b).
W is R’s son, so W belongs to the generation below R.
X is W’s daughter — one more generation down.
So X is R’s granddaughter.
Hence option (c).
Compare RBAT with TBAR: the FIRST and LAST letters swap (R ↔ T) while the middle pair B, A stays put.
Apply the same to MNPE: swap M and E.
That gives E, N, P, M.
Hence ENPM — option (b).
Each term = previous × 2 − 1.
3×2−1 = 5, 5×2−1 = 9, 9×2−1 = 17, 17×2−1 = 33, 33×2−1 = 65 ✓.
Next: 65 × 2 − 1 = 130 − 1.
= 129 — option (a).
Q+4 = U, N+4 = R, L+4 = P, D+4 = H — every letter moves +4.
Apply to FQDDBD: F+4 = J, Q+4 = U, D+4 = H.
D+4 = H, B+4 = F, D+4 = H.
Hence JUHHFH — option (a).
1st letters: B(2), K(11), T(20) — each +9 ⇒ next is 29 − 26 = 3 = C.
2nd letters: Y(25), R(18), K(11) — each −7 ⇒ next is 4 = D.
So the pair is C and D.
Hence CD — option (b).
F+1 = G, N+1 = O, Z+1 = A (cyclic), K+1 = L — every letter moves +1.
Apply to EZHK: E+1 = F, Z+1 = A.
H+1 = I, K+1 = L.
Hence FAIL — option (a).
Capital × time: X = 50,000 × 8 = 4,00,000; Y = 40,000 × 12 = 4,80,000.
Ratio = 400 : 480 = 5 : 6 (11 parts).
X’s share = × 33,000.
= ₹15,000 — option (b).
Rule: the first number raised to the power of the second.
Check: 11² = 121 ✓; 10² = 100 ✓.
15 # 2 = 15².
= 225 — option (a).
Taps and time are inversely proportional: T₁ × t₁ = T₂ × t₂.
8 × 30 = T₂ × 12.
T₂ = .
= 20 taps — option (b).
P, Q and R are siblings.
R is S’s mother, so P is S’s mother’s sister.
A mother’s sister is an aunt.
Hence option (a).
Replace the symbols: 35 + 5 × 10 − 2 becomes 35 − 5 ÷ 10 × 2.
BODMAS: 5 ÷ 10 = 0.5, then 0.5 × 2 = 1.
35 − 1 = 34.
Hence option (a).
Each term = previous × 2 + 1.
5×2+1 = 11, 11×2+1 = 23, 23×2+1 = 47, 47×2+1 = 95 ✓.
Next: 95 × 2 + 1 = 190 + 1.
= 191 — option (d).
Each term should be four times the previous: 9, 36, 144, 576, 2304, 9216.
The series shows 578 in place of 576 and 9218 in place of 9216.
So both those terms break the ×4 rule.
578 and 9218 — option (d).