Address matching
(b) drops 'No.'; (c) misspells 'Residncy'.
(d) changes the PIN to 600084.
Only (a) matches the sample exactly.
Hence option (a).
2
A statement is given followed by two conclusions. Find which conclusion is TRUE based on the given statement.Statement: D < B ≤ T = E ≥ O; G ≥ E < S; T ≥ B
Conclusions:
I. B ≤ O
II. D < G
A.Either I or II
B.Neither I nor II
C.Only I
D.Only II
Solution
Coded inequality
For I: B ≤ E and E ≥ O — the signs oppose at E, so B and O cannot be compared. I is false.
For II: D < B ≤ E and G ≥ E, so D < E ≤ G.
That chain gives D < G definitely — II is true.
Only II — option (d).
3
Read the given statement and conclusions carefully. Decide which of the given conclusions is/are definitely true from the statement.Statement: P = Q ≥ R ≤ S > T < U
Conclusions:
I. Q > U
II. R ≤ P
A.Only conclusion II is true
B.Neither conclusion I nor II is true
C.Both conclusions I and II are true
D.Only conclusion I is true
Solution
Coded inequality
P = Q ≥ R gives R ≤ P directly — II is true.
For I the chain runs Q ≥ R ≤ S > T < U, with the signs changing direction more than once.
So Q and U cannot be compared — I is false.
Only conclusion II — option (a).
4
C is the daughter of B. B is the son of D. How is D related to C?
A.Father
B.Mother
C.Grandparent
D.Uncle
Solution
Blood relation
B is the son of D, so B is one generation below D.
C is B’s daughter — one more generation down.
So D is two generations above C.
D is C’s grandparent — option (c).
5
P − Q means P is the sister of Q; P × Q means P is the mother of Q; P ÷ Q means P is the father of Q; P + Q means P is the brother of Q.
What is the relation in P × Q + R?
A.P is the mother of R
B.Q is the father of R
C.R is the mother of Q
D.Q is the brother of P
Solution
Symbol relations
P × Q: P is the mother of Q.
Q + R: Q is the brother of R, so Q and R are siblings.
Hence R is also a child of P.
P is the mother of R — option (a).
6
Read the statement and identify the action that follows.Statement: Cases of waterborne diseases have significantly increased in the city during the last six months.
Course of Action:
1. The municipal corporation should take immediate steps to ensure clean drinking water supply.
2. People should be advised to boil water before drinking.
A.Both follow
B.Only 1 follows
C.Only 2 follows
D.Neither follows
Solution
Course of action
Ensuring clean water supply tackles the root cause of the outbreak — 1 follows.
Advising people to boil water is a sound preventive measure meanwhile — 2 follows.
A long-term fix and an immediate precaution can run together.
Both follow — option (a).
7
Find the odd one out:
A.x5#
B.y6#
C.z7#
D.w8#
Solution
Alphabet order
The letters should run in alphabetical order alongside the rising numbers.
x, y, z follow one another with 5, 6, 7 ✓.
But w comes BEFORE x in the alphabet, yet carries 8 ✗.
Hence w8# — option (d).
8
Read the following statements carefully and identify the conclusion that follows.Statements:
All cars are vehicles.
Some vehicles are cycles.
No cycle is a car.
Conclusions:
I. Some cycles are cars.
II. Some vehicles are not cars.
A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Syllogism
"No cycle is a car" flatly contradicts I, so I cannot follow.
Some vehicles are cycles, and no cycle is a car — those vehicles are therefore not cars.
So II follows definitely.
Only II — option (b).
9
What comes next?
X, U, Q, L, ?
A.F
B.G
C.H
D.I
Solution
Letter series
Positions: X(24), U(21), Q(17), L(12) — the gaps are −3, −4, −5.
So the next gap is −6.
12 − 6 = 6, which is F.
Hence option (a).
10
Select the word that can be formed using the letters of the given word.
COMBATING
A.DAY
B.HOUSE
C.COAT
D.NOTE
Solution
Word from letters
COMBATING has C, O, M, B, A, T, I, N, G.
COAT needs C, O, A, T — all available ✓.
DAY needs D and Y, HOUSE needs H, U, S, E, and NOTE needs E — none are present.
Hence option (c).
11
Fill in the missing letter based on an alphabetical pattern.
C, E, G, I, ?
A.M
B.K
C.H
D.J
Solution
Letter series (+2)
Each letter moves two places forward.
C(3) → E(5) → G(7) → I(9).
9 + 2 = 11, which is K.
Hence option (b).
12
In a certain code, SLANO is written as TMBOP. How is SPEED written in that code?
A.TQFFE
B.TSQJO
C.TSBOJ
D.URBJO
Solution
Coding (+1)
Every letter moves +1: S+1 = T, L+1 = M, A+1 = B, N+1 = O, O+1 = P.
Apply to SPEED: S+1 = T, P+1 = Q, E+1 = F.
E+1 = F, D+1 = E.
Hence TQFFE — option (a).
13
Find the odd one out from the given alternatives.
A.Classical Languages
B.Hindi
C.Sanskrit
D.Marathi
Solution
Category vs member
Hindi, Sanskrit and Marathi are names of individual LANGUAGES.
"Classical Languages" is the name of a whole category, not a single language.
So it stands apart from the rest.
Hence option (a).
14
What comes next?
ZY, XW, VU, TS, RQ, ?
A.PO
B.PQ
C.PR
D.QP
Solution
Letter pairs (−2)
Each pair takes two consecutive letters written backwards.
The first letters go Z, X, V, T, R — each −2 ⇒ next is P.
The second letter is the one just before it, i.e. O.
Hence PO — option (a).
15
The sum of three consecutive even numbers is 60. What is the largest of these three numbers?
A.22
B.24
C.26
D.28
Solution
Consecutive even numbers
Let the numbers be x, x + 2 and x + 4.
3x + 6 = 60 ⇒ 3x = 54 ⇒ x = 18.
The numbers are 18, 20 and 22.
The largest is 22 — option (a).
16
Eligibility Criteria:
Should have passed Graduation with a minimum of 55% marks. Must have a minimum typing speed of 45 WPM. Should have completed a Diploma in Computer Applications (DCA). Age should be between 21 and 30 years only.
Case: Amit has completed his Graduation with 62% marks, types at 50 WPM, holds a DCA certificate and is 26 years old.
A.Eligible
B.Not eligible due to age
C.Not eligible due to typing speed
D.Not eligible due to missing certification
Solution
Eligibility check
Marks: 62% ≥ 55% ✓. Typing: 50 WPM ≥ 45 WPM ✓.
Certification: he holds a DCA ✓. Age: 26 lies between 21 and 30 ✓.
Every condition is satisfied.
Eligible — option (a).
17
If 'A' denotes '+', 'B' denotes '×', 'C' denotes '−' and 'D' denotes '÷', what is the value of the following expression?
6 B 2 A 4 C 3 D 1 = ?
If the signs are interchanged as follows: '+' means '×', '−' means '÷', '×' means '+' and '÷' means '−', choose the correct equation from the options below.
Shyam, who is suffering from an infectious disease, is admitted to a hospital. As a healthcare worker, what would be your first step?
A.Immediately isolate Shyam and inform the doctor on duty.
B.Ask Shyam to sit in the waiting area with other patients.
C.Have Shyam fill out the forms to complete the admission process.
D.Inform Shyam's family about the situation.
Solution
Ethics — infection control
An infectious patient can pass the disease to others in minutes.
Isolating him at once and calling the doctor protects both the patient and everyone around.
Seating him with other patients would spread the infection; forms and family calls can wait.
Hence option (a).
20
Given below is an equation which has to be solved by following the interchange, i.e. '+' becomes '−' and '−' becomes '+', '×' becomes '÷' and '÷' becomes '×'.
Then what is the value of 100 ÷ 4 + 30 − 50 × 10?
What should come at the place of the question mark?
97, 91, 82, 70, 55, ?
A.38
B.37
C.39
D.40
Solution
Series — falling gaps
Differences: −6, −9, −12, −15 — each gap grows by 3.
So the next gap is −18.
55 − 18 = 37.
Hence option (b).
22
Statements:
All pencils are erasers.
Some erasers are boxes.
Conclusions:
I. Some boxes are pencils.
II. All pencils are boxes.
A.Neither I nor II follows
B.Only Conclusion II follows
C.Both I and II follow
D.Only Conclusion I follows
Solution
Syllogism
Pencils lie inside erasers, and only SOME erasers are boxes.
The boxes may lie entirely in the part of the eraser group that has no pencils, so I is not certain.
II makes an even stronger claim and is certainly not established.
Neither follows — option (a).
23
If "BAT" is coded as "2-1-20", how will "TAB" be coded?
A.20-1-2
B.3-20-1
C.1-3-20
D.20-3-1
Solution
Place values
Each letter is replaced by its position: B = 2, A = 1, T = 20.
TAB uses the same letters in a new order.
T = 20, A = 1, B = 2.
= 20-1-2 — option (a).
24
If NARDEO is coded as MZQCDN, how is RZQBDO coded?
A.QYPCBJ
B.QYPACN
C.QYPCCN
D.FZQCDN
Solution
Coding (−1)
Every letter moves one step BACK: N−1 = M, A−1 = Z, R−1 = Q, D−1 = C, E−1 = D, O−1 = N.
Apply to RZQBDO: R−1 = Q, Z−1 = Y, Q−1 = P.
B−1 = A, D−1 = C, O−1 = N.
Hence QYPACN — option (b).
25
The series given below contains a sequence of numbers. Accordingly identify the incorrect combination.
4, 9, 12, 12, 36, 17, 108, 18, 325, 21
A.12, 325
B.36, 325
C.17, 325
D.36, 17
Solution
Two interleaved series
Odd places form 4, 12, 36, 108, 324 — each × 3; the series shows 325 instead of 324 ✗.
Even places form 9, 12, 15, 18, 21 — each + 3; the series shows 17 in place of 15 ✗.
So the two faulty terms are 17 and 325.
Hence option (c).
Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
B is the son of D, so B is one generation below D.
C is B’s daughter — one more generation down.
So D is two generations above C.
D is C’s grandparent — option (c).
P × Q: P is the mother of Q.
Q + R: Q is the brother of R, so Q and R are siblings.
Hence R is also a child of P.
P is the mother of R — option (a).
The letters should run in alphabetical order alongside the rising numbers.
x, y, z follow one another with 5, 6, 7 ✓.
But w comes BEFORE x in the alphabet, yet carries 8 ✗.
Hence w8# — option (d).
"No cycle is a car" flatly contradicts I, so I cannot follow.
Some vehicles are cycles, and no cycle is a car — those vehicles are therefore not cars.
So II follows definitely.
Only II — option (b).
Positions: X(24), U(21), Q(17), L(12) — the gaps are −3, −4, −5.
So the next gap is −6.
12 − 6 = 6, which is F.
Hence option (a).
COMBATING has C, O, M, B, A, T, I, N, G.
COAT needs C, O, A, T — all available ✓.
DAY needs D and Y, HOUSE needs H, U, S, E, and NOTE needs E — none are present.
Hence option (c).
Each letter moves two places forward.
C(3) → E(5) → G(7) → I(9).
9 + 2 = 11, which is K.
Hence option (b).
Every letter moves +1: S+1 = T, L+1 = M, A+1 = B, N+1 = O, O+1 = P.
Apply to SPEED: S+1 = T, P+1 = Q, E+1 = F.
E+1 = F, D+1 = E.
Hence TQFFE — option (a).
Each pair takes two consecutive letters written backwards.
The first letters go Z, X, V, T, R — each −2 ⇒ next is P.
The second letter is the one just before it, i.e. O.
Hence PO — option (a).
Let the numbers be x, x + 2 and x + 4.
3x + 6 = 60 ⇒ 3x = 54 ⇒ x = 18.
The numbers are 18, 20 and 22.
The largest is 22 — option (a).
Marks: 62% ≥ 55% ✓. Typing: 50 WPM ≥ 45 WPM ✓.
Certification: he holds a DCA ✓. Age: 26 lies between 21 and 30 ✓.
Every condition is satisfied.
Eligible — option (a).
Replace the letters: 6 × 2 + 4 − 3 ÷ 1.
BODMAS: 6 × 2 = 12 and 3 ÷ 1 = 3.
12 + 4 − 3 = 16 − 3.
= 13 — option (b).
Check option (a): 8 + 2 × 3 becomes 8 × 2 + 3.
BODMAS: 8 × 2 = 16.
16 + 3 = 19 = RHS ✓.
Hence option (a).
Replace the symbols: 100 × 4 − 30 + 50 ÷ 10.
BODMAS: 100 × 4 = 400 and 50 ÷ 10 = 5.
400 − 30 + 5.
= 375 — option (d).
Differences: −6, −9, −12, −15 — each gap grows by 3.
So the next gap is −18.
55 − 18 = 37.
Hence option (b).
Pencils lie inside erasers, and only SOME erasers are boxes.
The boxes may lie entirely in the part of the eraser group that has no pencils, so I is not certain.
II makes an even stronger claim and is certainly not established.
Neither follows — option (a).
Each letter is replaced by its position: B = 2, A = 1, T = 20.
TAB uses the same letters in a new order.
T = 20, A = 1, B = 2.
= 20-1-2 — option (a).
Every letter moves one step BACK: N−1 = M, A−1 = Z, R−1 = Q, D−1 = C, E−1 = D, O−1 = N.
Apply to RZQBDO: R−1 = Q, Z−1 = Y, Q−1 = P.
B−1 = A, D−1 = C, O−1 = N.
Hence QYPACN — option (b).
Odd places form 4, 12, 36, 108, 324 — each × 3; the series shows 325 instead of 324 ✗.
Even places form 9, 12, 15, 18, 21 — each + 3; the series shows 17 in place of 15 ✗.
So the two faulty terms are 17 and 325.
Hence option (c).