SSC CGL 22 September 2025 · Shift 3 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 129 of 192
22 September 2025 · Shift 3
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
Choose the address that is the same as the one given below.
Apartment 2B, Green Towers, Nungambakkam, Karnataka, Bangalore - 560001
A.Apartment 2B, Green Towers, Nungambakkam, Karnatka, Bangalore - 560001
B.Apartment 2B, Green Towers, Nungambakkam, Karnataka, Bangalore - 560001
C.Apartment 2B, Green Tower, Nungambakkam, Karnataka, Bangalore - 560001
D.Apartment 2B, Green Towers, Nungambakam, Karnataka, Bangalore - 560001
Solution
Address matching
Compare each option with the sample piece by piece.
(a) misspells 'Karnatka' and (c) writes 'Green Tower' without the s.
(d) misspells 'Nungambakam'.
Only (b) reproduces every part correctly — option (b).
2
Which two signs should be interchanged to make the equation correct?
15 × 5 − 20 ÷ 4 + 6 = 74
The given statements are followed by two conclusions. Find out which conclusion is TRUE based on the given statements.Statements: A > B = C, D ≥ E < B, F < A < G, E = H ≥ I
Conclusions:
I. D > I
II. D = I
A.Neither conclusion I nor II is true
B.Both conclusion I and II are true
C.Either conclusion I or II is true
D.Only conclusion II is true
Solution
Either-or case
Combine the chains: D ≥ E = H ≥ I, so D ≥ I.
That means D is either greater than I or equal to I, but we cannot say which.
Neither I nor II is individually certain, yet one of them must hold.
This is the classic either-or case — option (c).
4
M is the daughter of N. N is the son of O. How is M related to O?
A.Niece
B.Granddaughter
C.Aunt
D.Sister
Solution
Blood relation
N is the son of O, so N is one generation below O.
M is N’s daughter — one more generation down.
So M is two generations below O and is female.
M is O’s granddaughter — option (b).
5
Read the following statement carefully and identify the action that follows.Statement: A manager discovers financial irregularities in the accounts.
Course of Action:
1. Conduct an internal audit.
2. Take strict action against guilty staff.
A.Only 1
B.Only 2
C.Both follow
D.Neither follows
Solution
Course of action
An internal audit is the proper first step to establish the extent of the problem — 1 follows.
Once guilt is established, strict action deters further wrongdoing — 2 follows.
Investigation and consequence go together.
Both follow — option (c).
6
You are a receptionist in a hospital. You see an elderly patient struggling to fill out a registration form, appearing distressed and having difficulty writing their information. What should you do?
A.Let them fill out the form themselves, as it is against hospital policy for staff to provide personal assistance.
B.Ask them to move to a different waiting area without any explanation.
C.Approach them and politely ask if they need assistance, and if they agree, help them fill out the form.
D.Ignore them, assuming a family member will be accompanying them.
Solution
Ethics — helping a patient
A receptionist’s duty includes helping patients complete formalities.
Asking politely respects the patient’s dignity and consent before helping.
The other options are either untrue about policy or plainly uncaring.
Hence option (c).
7
Identify the number which is different from the other options:
A.11
B.13
C.17
D.15
Solution
Prime numbers
11, 13 and 17 are all PRIME numbers.
15 = 3 × 5, so it is composite.
So it breaks the pattern.
Hence option (d).
8
Read the following statements carefully and identify the conclusion that follows.Statements:
No cow is a buffalo.
Some buffaloes are pets.
All pets are friendly.
Conclusions:
I. Some pets are not cows.
II. All buffaloes are friendly.
A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Syllogism
Some buffaloes are pets, and no cow is a buffalo — so those pets are certainly not cows, and I follows.
Only SOME buffaloes are said to be pets, so nothing can be claimed about all of them.
II therefore does not follow.
Only I — option (a).
9
What comes next?
C, F, J, O, U, ?
A.B
B.C
C.D
D.A
Solution
Series — rising gaps
Positions: C(3), F(6), J(10), O(15), U(21) — the gaps are +3, +4, +5, +6.
So the next gap is +7: 21 + 7 = 28.
Counting cyclically, 28 − 26 = 2.
The 2nd letter is B — option (a).
10
From the given alternative words, select the word which can be formed using the letters of the given word.
APPLE
A.PASE
B.PIPE
C.LEAP
D.PLEN
Solution
Word from letters
APPLE has the letters A, P, P, L, E.
LEAP needs L, E, A, P — all available ✓.
PASE needs S, PIPE needs I and PLEN needs N — none are present.
Hence option (c).
11
What comes next in the series?
X, V, T, R, ?
A.S
B.O
C.P
D.Q
Solution
Letter series (−2)
Each letter moves two places back.
X(24) → V(22) → T(20) → R(18).
18 − 2 = 16, which is P.
Hence option (c).
12
Which meaningful word can be formed from the letters "CLEPIN"?
A.CLEAP
B.CLEAN
C.PENCIL
D.PLACE
Solution
Jumbled word
The six letters are C, L, E, P, I, N.
Rearranged they spell PENCIL.
CLEAN and PLACE need an A, which is not there; CLEAP is not a word.
Hence option (c).
13
If FOLDER is written as SFEMPG, how is DESIGN written?
A.OJHTFE
B.OHJTFE
C.NGISED
D.OFJUGF
Solution
Reverse and +1
Reverse FOLDER to get REDLOF, then add 1 to each letter: R+1 = S, E+1 = F, D+1 = E, L+1 = M, O+1 = P, F+1 = G ⇒ SFEMPG ✓.
Reverse DESIGN to get NGISED.
Add 1 to each: N+1 = O, G+1 = H, I+1 = J, S+1 = T, E+1 = F, D+1 = E.
Hence OHJTFE — option (b).
14
Find the odd one out from the given alternatives.
A.HTML
B.CSS
C.JavaScript
D.MySQL
Solution
Web languages vs database
HTML, CSS and JavaScript are all used to build and style web pages.
MySQL is a database management system used to store and manage data.
So it serves a different purpose.
Hence option (d).
15
A tank can be filled by an inlet pipe in 10 hours. Another outlet pipe can empty the same tank in 15 hours. If both pipes are opened simultaneously, how long will it take to fill the empty tank completely?
A.30 h
B.10 h
C.25 h
D.15 h
Solution
Inlet and outlet pipes
Take the tank as LCM(10, 15) = 30 units.
Inlet fills = 3 units per hour; outlet empties = 2 units per hour.
Net rate = 3 − 2 = 1 unit per hour.
Time = = 30 hours — option (a).
16
You work at a community health centre and someone reports serious mental health problems. What should you do?
A.Guide them to the necessary support and resources
B.Dismiss it as a private matter
C.Ask them to come back later
D.Send them directly to a psychiatrist without any initial assessment
Solution
Ethics — mental health
A health worker’s duty is to connect the person with appropriate care.
Guiding them to the right support and resources is both prompt and responsible.
Dismissing or delaying can worsen the condition; sending them on without any assessment skips the first step of care.
Hence option (a).
17
Which interchanges of numbers and signs will make the equation correct?
8 + 4 × 5 = 28
A.+ and ×, 4 and 5
B.+ and ×, 8 and 5
C.+ and ×, 8 and 4
D.+ and ×, 28 and 8
Solution
Interchange numbers and signs
Take option (b): swap + with × and also swap the numbers 8 and 5.
The equation becomes 5 × 4 + 8.
5 × 4 = 20, then 20 + 8.
= 28 ✓ — option (b).
18
If 'P' denotes '+', 'Q' denotes '−', 'R' denotes '×' and 'S' denotes '÷', what is the value of the following expression?
10 P 2 R 4 Q 2 = ?
What should come at the place of the question mark?
7, 14, 24, 37, 53, ?
A.72
B.69
C.74
D.71
Solution
Series — rising gaps
Differences: 7, 10, 13, 16 — each rises by 3.
So the next difference is 19.
53 + 19 = 72.
Hence option (a).
20
Statements:
Some cars are buses.
All buses are rickshaws.
Conclusions:
I. All cars are buses.
II. Some rickshaws are buses.
A.Only Conclusion II follows
B.Only Conclusion I follows
C.Neither I nor II follows
D.Both I and II follow
Solution
Syllogism
All buses are rickshaws, so the buses themselves form a part of the rickshaw group — II follows.
The first statement says only SOME cars are buses.
So "all cars are buses" cannot be concluded — I does not follow.
Only Conclusion II — option (a).
21
If + = ×, − = ÷, × = + and ÷ = −, then 75 − 5 + 4 × 8 = ?
If 'PEN' is coded as '16-5-14', how will 'NEP' be coded?
A.14-5-16
B.16-14-5
C.5-14-16
D.14-16-5
Solution
Place values
Each letter is replaced by its position: P = 16, E = 5, N = 14.
NEP uses the same letters in a new order.
N = 14, E = 5, P = 16.
= 14-5-16 — option (a).
23
If TABLE is coded as UBCMF, how is UBCMF coded?
A.VCDNG
B.VCDNF
C.VBCMF
D.UBCLF
Solution
Coding (+1)
Every letter moves +1: T+1 = U, A+1 = B, B+1 = C, L+1 = M, E+1 = F.
Apply the same rule again to UBCMF: U+1 = V, B+1 = C, C+1 = D.
M+1 = N, F+1 = G.
Hence VCDNG — option (a).
24
P, Q, R, S, T and U are the six members of a family. P is the male member of a married pair, P and Q. R is P's brother, and S is his only son. S has a sister named T. U's husband has passed away, and Q is her daughter-in-law. What connection does T have to R?
A.Sister
B.Daughter
C.Cousin
D.Mother-in-law
Solution
Family relation
U is the mother of P and R, since Q — P’s wife — is her daughter-in-law.
"S is his only son" refers to R, and T is S’s sister, so both are R’s children.
T is therefore R’s daughter.
Hence option (b).
25
The series given below contains a sequence of numbers. Accordingly identify the incorrect number.
2, 3, 8, 27, 111
A.27
B.8
C.111
D.3
Solution
Wrong term in series
The rule is ×1 + 1, ×2 + 2, ×3 + 3, ×4 + 4.
2×1 + 1 = 3 ✓, 3×2 + 2 = 8 ✓, 8×3 + 3 = 27 ✓.
27×4 + 4 = 112, but the series shows 111 ✗.
Hence 111 — option (c).
Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
Interchange + and − : the equation becomes 15 × 5 + 20 ÷ 4 − 6.
BODMAS: 15 × 5 = 75 and 20 ÷ 4 = 5.
75 + 5 − 6 = 80 − 6.
= 74 ✓ — option (d).
Combine the chains: D ≥ E = H ≥ I, so D ≥ I.
That means D is either greater than I or equal to I, but we cannot say which.
Neither I nor II is individually certain, yet one of them must hold.
This is the classic either-or case — option (c).
N is the son of O, so N is one generation below O.
M is N’s daughter — one more generation down.
So M is two generations below O and is female.
M is O’s granddaughter — option (b).
11, 13 and 17 are all PRIME numbers.
15 = 3 × 5, so it is composite.
So it breaks the pattern.
Hence option (d).
Some buffaloes are pets, and no cow is a buffalo — so those pets are certainly not cows, and I follows.
Only SOME buffaloes are said to be pets, so nothing can be claimed about all of them.
II therefore does not follow.
Only I — option (a).
Positions: C(3), F(6), J(10), O(15), U(21) — the gaps are +3, +4, +5, +6.
So the next gap is +7: 21 + 7 = 28.
Counting cyclically, 28 − 26 = 2.
The 2nd letter is B — option (a).
APPLE has the letters A, P, P, L, E.
LEAP needs L, E, A, P — all available ✓.
PASE needs S, PIPE needs I and PLEN needs N — none are present.
Hence option (c).
Each letter moves two places back.
X(24) → V(22) → T(20) → R(18).
18 − 2 = 16, which is P.
Hence option (c).
The six letters are C, L, E, P, I, N.
Rearranged they spell PENCIL.
CLEAN and PLACE need an A, which is not there; CLEAP is not a word.
Hence option (c).
Reverse FOLDER to get REDLOF, then add 1 to each letter: R+1 = S, E+1 = F, D+1 = E, L+1 = M, O+1 = P, F+1 = G ⇒ SFEMPG ✓.
Reverse DESIGN to get NGISED.
Add 1 to each: N+1 = O, G+1 = H, I+1 = J, S+1 = T, E+1 = F, D+1 = E.
Hence OHJTFE — option (b).
HTML, CSS and JavaScript are all used to build and style web pages.
MySQL is a database management system used to store and manage data.
So it serves a different purpose.
Hence option (d).
Take the tank as LCM(10, 15) = 30 units.
Inlet fills = 3 units per hour; outlet empties = 2 units per hour.
Net rate = 3 − 2 = 1 unit per hour.
Time = = 30 hours — option (a).
Take option (b): swap + with × and also swap the numbers 8 and 5.
The equation becomes 5 × 4 + 8.
5 × 4 = 20, then 20 + 8.
= 28 ✓ — option (b).
Replace the letters: 10 + 2 × 4 − 2.
BODMAS: 2 × 4 = 8.
10 + 8 − 2 = 18 − 2.
= 16 — option (b).
Differences: 7, 10, 13, 16 — each rises by 3.
So the next difference is 19.
53 + 19 = 72.
Hence option (a).
All buses are rickshaws, so the buses themselves form a part of the rickshaw group — II follows.
The first statement says only SOME cars are buses.
So "all cars are buses" cannot be concluded — I does not follow.
Only Conclusion II — option (a).
Replace the symbols: 75 ÷ 5 × 4 + 8.
BODMAS: 75 ÷ 5 = 15, then 15 × 4 = 60.
60 + 8.
= 68 — option (a).
Each letter is replaced by its position: P = 16, E = 5, N = 14.
NEP uses the same letters in a new order.
N = 14, E = 5, P = 16.
= 14-5-16 — option (a).
Every letter moves +1: T+1 = U, A+1 = B, B+1 = C, L+1 = M, E+1 = F.
Apply the same rule again to UBCMF: U+1 = V, B+1 = C, C+1 = D.
M+1 = N, F+1 = G.
Hence VCDNG — option (a).
U is the mother of P and R, since Q — P’s wife — is her daughter-in-law.
"S is his only son" refers to R, and T is S’s sister, so both are R’s children.
T is therefore R’s daughter.
Hence option (b).
The rule is ×1 + 1, ×2 + 2, ×3 + 3, ×4 + 4.
2×1 + 1 = 3 ✓, 3×2 + 2 = 8 ✓, 8×3 + 3 = 27 ✓.
27×4 + 4 = 112, but the series shows 111 ✗.
Hence 111 — option (c).