Chapter 149 of 192
General Intelligence & Reasoning
Each letter is worth five times its position.
A is 1st ⇒ 5, C is 3rd ⇒ 15.
E is 5th ⇒ 25.
= 5, 15, 25 — option (a).
Nagpur’s seminar was on 7 March.
Two days later means 7 + 2 = 9 March.
The seminar on 9 March was at Indore.
Hence option (b).
Rule: first number − twice the second number.
Check: 14 − 2×4 = 6 ✓ and 17 − 2×6 = 5 ✓.
20 − 2×8 = 20 − 16.
= 4 — option (a).
Rule: a % b = a − b.
Check: 9 − 4 = 5 ✓ and 8 − 3 = 5 ✓.
7 − 2.
= 5 — option (c).
Rule: a # b = a² − 1 (the second number is always one less than the first).
Check: 3² − 1 = 8 ✓, 4² − 1 = 15 ✓, 5² − 1 = 24 ✓.
6² − 1 = 36 − 1.
= 35 — option (a).
Argentina, Brazil and Chile all lie in SOUTH AMERICA.
Japan is in East Asia.
So it belongs to a different continent.
Hence option (c).
Q is R’s daughter, so Q is one generation below R.
P is Q’s daughter — one more generation down.
P is therefore two generations below R and is female.
P is R’s granddaughter — option (a).
Rule: the square of the number multiplied by the next number.
Check: 7² × 8 = 49 × 8 = 392 ✓.
8² × 9 = 64 × 9.
= 576 — option (b).
Roses lie inside flowers and flowers inside plants, so all roses are plants — I follows.
Since all flowers are plants, at least some plants are certainly flowers — II follows.
Both are direct consequences of the chain.
Both follow — option (c).
"Some teachers are careless" simply reverses into "some careless people are teachers" — II follows.
Only SOME teachers are careless; the rest may well be students.
So a complete separation of teachers and students is not certain — I does not follow.
Only II — option (b).
All four begin with "gar", so compare the fourth letter.
They are a (garage), b (garbage), d (garden) and m (garment).
"a" comes earliest in the alphabet.
So garage comes first — option (b).
In each pair the number should be the place value of the letter.
E = 5 ✓, G = 7 ✓, K = 11 ✓ and M = 13 ✓.
But I is the 9th letter, so it should have been I9, not I8 ✗.
Hence I8 — option (b).
Each term = previous × 2 − 1.
2×2−1 = 3, 3×2−1 = 5 ✓.
So the missing term is 5 × 2 − 1 = 9, and then 9×2−1 = 17 ✓ and 17×2−1 = 33 ✓.
= 9 — option (d).
The series should rise by 3 each time — the multiples of 3.
3, 6, 9, 12, then 15, then 18.
The series shows 14 instead of 15 ✗.
Hence option (d).
Each pair is a letter with its place value: M = 13, N = 14, L = 12, O = 15.
The letters move +1, −2, +3, then −4 from the starting point M.
After O(15) the next step is −4: 15 − 4 = 11, which is K.
Hence K11 — option (a).
Each term is the previous one divided by 6.
1296 ÷ 6 = 216, 216 ÷ 6 = 36, 36 ÷ 6 = 6 ✓.
Next: 6 ÷ 6 = 1, then 1 ÷ 6 ≈ 0.16.
= 1, 0.16 — option (c).
Sphere = πr³.
Cylinder = πr²h, with h = 2r, so it equals 2πr³.
Ratio = πr³ : 2πr³ = : 2.
= 2 : 3 — option (a).
Lines 1 and 2 share "moon" and the common code la ⇒ moon = la.
Line 3 gives sky and sun as sa and pa, and line 2 confirms sky = sa, so sun = pa.
In line 1 the codes pa (sun) and la (moon) are used up.
The one left, ra, must stand for star — option (a).
The code simply writes the word backwards: TABLE → ELBAT.
Reverse CHAIR letter by letter.
C-H-A-I-R becomes R-I-A-H-C.
= RIAHC — option (a).
Replace the symbols: 8 × 2 ÷ 4 − 2 + 3.
BODMAS: 8 × 2 = 16, then 16 ÷ 4 = 4.
4 − 2 + 3.
= 5 — option (b).
x + y = 50 and x − y = 6.
Adding: 2x = 56 ⇒ x = 28, so y = 22.
Product = 28 × 22.
= 616 — option (c).
Profit on one pen = 8 − 5 = ₹3.
He repeats the deal 60 times.
Total profit = 3 × 60.
= ₹180 — option (c).
Every letter moves +1: T+1 = U, R+1 = S, A+1 = B, I+1 = J, N+1 = O.
Apply the same rule again to USBJO: U+1 = V, S+1 = T, B+1 = C.
J+1 = K, O+1 = P.
Hence VTCKP — option (a).
Every letter moves +3: L+3 = O, I+3 = L, G+3 = J, H+3 = K, T+3 = W.
Apply to BRIGHT: B+3 = E, R+3 = U, I+3 = L.
G+3 = J, H+3 = K, T+3 = W.
Hence EULJKW — option (a).Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
