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SSC CGL 26 September 2025 · Shift 1 · General Intelligence & Reasoning — questions with answers · ShikshaSphere

Chapter 169 of 192

26 September 2025 · Shift 1

General Intelligence & Reasoning

25 questions ~25 min readFree

25 questions

An entrepreneurship summit in Mumbai was held on 10th January. Delhi hosted it five days later. When was the Delhi event?

A.4th January
B.15th January
C.10th January
D.20th January

Solution

Date reasoning

The Mumbai summit was on 10 January. Delhi hosted it five days later. 10 + 5. = 15 January — option (b).

Choose the address that is the same as the one given below. Room 210, Admin Block, IIT Delhi, Hauz Khas, Delhi - 110016

A.Room 210, Admin Block, IIT Delhi, Hauz Khas, Delhi - 110016
B.Room 210, Admin Block, IIT Delhii, Hauz Khas, Delhi - 110016
C.Room 210, Admin Block, IIT Delhi, Haozkhas, Delhi - 110016
D.Room 210, Academic Block, IIT Delhi, Hauz Khas, Delhi - 110016

Solution

Address matching (b) spells Delhii with a double i and (c) writes Haozkhas for Hauz Khas. (d) changes Admin Block to Academic Block. Only (a) matches the sample exactly. Hence option (a).

If 3 # 3 = 18 and 4 # 4 = 32, then 5 # 5 = ?

A.48
B.50
C.45
D.49

Solution

a² × 2

Rule: multiply the two numbers and double the product, i.e. a² × 2. Check: 3² × 2 = 18 ✓ and 4² × 2 = 32 ✓. 5² × 2 = 25 × 2. = 50 — option (b).

If P # Q = P × Q − P, what is 8 # 6?

A.40
B.35
C.30
D.48

Solution

P × Q − P

Substitute P = 8 and Q = 6 in the given rule. 8 × 6 = 48. 48 − 8. = 40 — option (a).

Which two signs should be swapped to correct this equation? 20 + 5 × 3 ÷ 3 − 1 = 14

A.÷ and +
B.+ and ×
C.× and +
D.× and −

Solution

Swap two signs

As it stands, 5 × 3 ÷ 3 = 5, so the left side is 20 + 5 − 1 = 24 ✗. Swap ÷ and +: the equation becomes 20 ÷ 5 × 3 + 3 − 1. BODMAS: 20 ÷ 5 = 4, then 4 × 3 = 12. 12 + 3 − 1 = 14 ✓ — option (a).

Find the ODD one out.

A.8765
B.7654
C.6543
D.3456

Solution

Descending digits

In 8765, 7654 and 6543 the digits fall by one each time. In 3456 the digits RISE by one each time. So its pattern runs the other way. Hence option (d).

Identify the odd city.

A.Lucknow
B.Jaipur
C.Pune
D.Bhopal

Solution

State capitals

Lucknow, Jaipur and Bhopal are the capitals of Uttar Pradesh, Rajasthan and Madhya Pradesh. Pune is not a capital — Mumbai is the capital of Maharashtra. So it stands apart from the rest. Hence option (c).

If we increase each even digit by 1 and decrease each odd digit by 1 in the number 4729253684, and then arrange all the digits in descending order, what is the sum of the last five digits from the right end after the rearrangement?

A.17
B.20
C.28
D.15

Solution

Digit operations

Apply the rule digit by digit: 4→5, 7→6, 2→3, 9→8, 2→3, 5→4, 3→2, 6→7, 8→9, 4→5. The new digits are 5, 6, 3, 8, 3, 4, 2, 7, 9, 5. In descending order: 9, 8, 7, 6, 5, 5, 4, 3, 3, 2 — the last five from the right are 5, 4, 3, 3, 2. 5 + 4 + 3 + 3 + 2 = 17 — option (a).

Solve: KM : NP : DF : ?

A.PN
B.GI
C.OP
D.QR

Solution

Letter pairs, gap 2

In each pair the second letter is two places after the first. K(11) → M(13), N(14) → P(16), D(4) → F(6) ✓. Among the options only GI keeps that gap: G(7) → I(9). Hence GI — option (b).

Choose the number that fits the analogy: 4 : 60 :: 5 : ?

A.130
B.120
C.125
D.124

Solution

n³ − n

Rule: cube the number and subtract the number itself. Check: 4³ − 4 = 64 − 4 = 60 ✓. 5³ − 5 = 125 − 5. = 120 — option (b).

Read the following statement carefully and identify the action that follows. Statement: A recent survey shows increasing screen time among teenagers. Courses of Action: I. Ban all social media platforms for teenagers. II. Promote outdoor activities and limit daily screen usage.

A.Only II follows
B.Only I follows
C.Neither follows
D.Both follow

Solution

Course of action A course of action must be practical and proportionate to the problem. A blanket ban on all social media is extreme and cannot be enforced — I does not follow. Encouraging outdoor activity and setting a sensible screen limit tackles the problem directly — II follows. Only II — option (a).

Study the following information carefully and answer the question. Six people P, Q, R, S, T and U live in a six-storey building; the lowest floor is numbered 1 and the highest 6. T lives on an even-numbered floor. There are 2 floors between T and Q and 1 floor between T and U. R lives on the first floor. U does not live immediately above R. There are 2 people between P and S. S does not live on an odd floor. Who lives 2 floors below Q?

Solution

Floor arrangement

R is on floor 1 and T is on an even floor. U is 1 floor away from T but not on floor 2, so T = 2 and U = 4. With 2 floors between T and Q, Q sits on floor 5. S must be on an even floor, and 2 and 4 are taken, so S = 6; then P takes floor 3, leaving 2 people between P and S ✓. Q is on 5, so 2 floors below is floor 3 — P, option (a).

Read the following statements carefully and identify the conclusion that follows. Statements: No mango is red. All cherries are mangoes. Conclusions: I. No cherry is red. II. Some mangoes are cherries.

A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows

Solution

Syllogism

All cherries lie inside the mango group, and no mango is red. So no cherry can be red — I follows. "All cherries are mangoes" converts into "some mangoes are cherries" — II follows. Both follow — option (c).

Read the following statements carefully and identify the conclusion that follows. Statements: All books are notebooks. Some notebooks are not diaries. No diary is a ruler. Conclusions: I. Some books are not rulers. II. All rulers are diaries.

A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows

Solution

Syllogism

Books lie inside notebooks, but the notebooks that are NOT diaries need not be the books. So nothing fixes books against rulers — books could all be rulers, and I is not certain ✗. "No diary is a ruler" keeps diaries and rulers apart; it never makes rulers a part of diaries — II is false ✗. Neither follows — option (d).

Find the odd one out.

A.Nile
B.Amazon
C.Ganga
D.Everest

Solution

Rivers vs mountain

The Nile, the Amazon and the Ganga are all RIVERS. Everest is a mountain peak. So it belongs to a different category. Hence option (d).

What comes next in the series? A, C, F, J, O, ?

Solution

Rising letter gaps

Positions: A(1), C(3), F(6), J(10), O(15) — the gaps are +2, +3, +4, +5. So the next gap is +6. 15 + 6 = 21. The 21st letter is U — option (d).

What is the next number in the series? 200, 100, 50, ?

A.35
B.25
C.30
D.20

Solution

Series (÷2)

Each term is half the previous one. 200 ÷ 2 = 100 and 100 ÷ 2 = 50 ✓. 50 ÷ 2. = 25 — option (b).

In a certain code, "GLASS" is written as "FKZRR". What is the code for CLEAN?

A.BKDZM
B.BKDMZ
C.BJDZM
D.BKZQS

Solution

Coding (−1)

Every letter moves one place back: G−1 = F, L−1 = K, A−1 = Z (cyclic), S−1 = R, S−1 = R ✓. Apply to CLEAN: C−1 = B, L−1 = K, E−1 = D. A−1 = Z, N−1 = M. Hence BKDZM — option (a).

Complete the series. 4, 7, 11, 16, 22, 29, ?

A.37
B.35
C.30
D.39

Solution

Rising differences

The differences are 3, 4, 5, 6, 7 — each one more than the last. So the next difference is 8. 29 + 8. = 37 — option (a).

What comes next? B3, X24, C4, W23, ?

A.V22
B.D5
C.F6
D.U21

Solution

Letter with place value The terms alternate between the start and the end of the alphabet, each paired with its place value plus one. Start side: B3, C4 — so the next in that chain is D5. End side: X24, W23 — that chain gives V22 next, but it is the start side’s turn. Hence D5 — option (b).

In the following examples a number is coded as three digits — the remainders when the number is divided by 3, 7 and 11 respectively. Example 1: 73 → (73 ÷ 3 = 24 R1, 73 ÷ 7 = 10 R3, 73 ÷ 11 = 6 R7) → Code: 1, 3, 7 Example 2: 118 → (118 ÷ 3 = 39 R1, 118 ÷ 7 = 16 R6, 118 ÷ 11 = 10 R8) → Code: 1, 6, 8 By this method, which of the given numbers would have the code 2, 5, 5?

A.236
B.323
C.233
D.243

Solution

Remainder code

Test each option against all three divisors. 236 ÷ 3 = 78 R2 ✓, 236 ÷ 7 = 33 R5 ✓, 236 ÷ 11 = 21 R5 ✓. 323 ÷ 7 leaves 1, 233 ÷ 7 leaves 2 and 243 ÷ 3 leaves 0 — all fail. Only 236 gives 2, 5, 5 — option (a).

Find the missing number: 81 : 729 :: 49 : ?

A.350
B.243
C.343
D.512

Solution

Square to cube

81 = 9² and 729 = 9³, so the square of a number is paired with its cube. 49 = 7². So the answer is 7³. = 343 — option (c).

A nurse is caring for a patient who insists on leaving the hospital against medical advice despite having a serious condition. What should the nurse do?

A.Allow the patient to leave without any discussion
B.Try to explain the risks and record the patient’s decision in writing
C.Call security to stop the patient from leaving
D.Ignore the situation and focus on other patients

Solution

Ethical judgement A competent adult patient has the right to refuse treatment and to leave. But the nurse also has a duty to inform and to keep a record. So the risks must be explained and the decision documented in writing. Forcing the patient to stay or ignoring the matter would both be wrong — option (b).

A father is 5 times as old as his daughter, and in 30 years he will be twice as old as his daughter will be then. How old is the daughter now?

A.10
B.14
C.16
D.9

Solution

Ages

Let the daughter be x years, so the father is 5x. After 30 years: 5x + 30 = 2(x + 30). 5x + 30 = 2x + 60 ⇒ 3x = 30. x = 10 years — option (a).

If in a code APPLE is written as BOQMG, then how is MANGO written?

A.NZOHQ
B.BOQLE
C.NRQLF
D.BQQMF

Solution

Position-wise shifts

Compare APPLE with BOQMG: A+1 = B, P−1 = O, P+1 = Q, L+1 = M, E+2 = G. So the shifts by position are +1, −1, +1, +1, +2. Apply to MANGO: M+1 = N, A−1 = Z (cyclic), N+1 = O, G+1 = H, O+2 = Q. Hence NZOHQ — option (a).

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