SSC CGL 15 September 2025 · Shift 2 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 41 of 192
15 September 2025 · Shift 2
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
Which is the 2nd last word in the sentence "Software development is progressing very quickly"?
A.is
B.quickly
C.very
D.progressing
Solution
Word position
Number the words: Software(1) development(2) is(3) progressing(4) very(5) quickly(6).
The last word is quickly (6th).
The 2nd last is the 5th word — very.
Hence option (c).
2
Choose the address that is exactly the same as the one given below.
C-205, Lotus Heights, Whitefield Main Road, Bengaluru, Karnataka - 560066
A.C-205, Lotus Heigts, Whitefield Main Road, Bengaluru, Karnataka - 560266
B.C-205, Lotus Heights, Whitefield Main Road, Bengaluru, Karnataka - 560066
C.C-205, Lotus Heights, Whitefield Rd, Bengaluru, Karnataka - 560066
D.C-205, Lotus Heights, Whitefield Main Road, Bangaluru, Karnataka - 560066
Solution
Address matching
(a) misspells 'Heigts' and changes the PIN to 560266.
(c) shortens 'Main Road' to 'Rd'; (d) writes 'Bangaluru'.
Only (b) matches every character.
Hence option (b).
3
Which of the following alternatives will replace the question mark?
Eta, Theta, Iota, Kappa, ?
A.Nu
B.Mu
C.Lambda
D.Xi
Solution
Greek alphabet order
These are consecutive letters of the Greek alphabet.
Order: … Eta (7th), Theta (8th), Iota (9th), Kappa (10th) …
The 11th Greek letter is Lambda (then Mu, Nu, Xi).
Hence option (c).
4
Which of the following alternative will fill the blanks?
qr_tu_rs_uq_stu
A.s, q, t, r
B.r, q, t, s
C.s, r, q, t
D.t, s, r, q
Solution
Repeating block
The 15 letters split into three blocks of 5: qr_tu / _rs_u / q_stu.
Each block is the word qrstu repeated.
Blanks in order: s, q, t, r.
Hence option (a).
5
X says, "My mother's husband's only son is Y." (X and Y are not the same) How is X related to Y?
A.Sister
B.Son
C.Father
D.Wife
Solution
Blood relation
X's mother's husband is X's father.
His ONLY son is Y — so X, being his child but not Y, cannot be a son.
X must be a daughter — Y’s sister.
Hence option (a).
6
X is Y's mother. Z is Y's father. How is Z related to X?
A.Husband
B.Brother
C.Son
D.Cousin
Solution
Blood relation
X is the mother and Z is the father of the same child Y.
So X and Z are the parents — a married couple.
Z is X’s husband.
Hence option (a).
Doubling series
Each term is roughly double the previous: 6 → 14 → 30 → 62 → 128.
The last step 62 → 128 and the sequence keep doubling.
128 × 2 = 256.
Hence option (d).
9
Find the odd one out:
A.5 @ 2 = 14
B.7 @ 3 = 22
C.6 @ 3 = 18
D.4 @ 4 = 16
Solution
Odd rule ((a+b)×2)
Rule: a @ b = (a + b) × 2.
(5+2)×2 = 14 ✓, (6+3)×2 = 18 ✓, (4+4)×2 = 16 ✓.
(7+3)×2 = 20, not 22.
Hence option (b) is the odd one.
10
Statement: Despite growing interest among buyers, solar-powered home batteries remain considerably more expensive than conventional batteries, and government incentives are necessary to encourage their use.Assumptions:
I. The high price is a major obstacle to widespread adoption of solar-powered batteries.
II. Government incentives can make solar-powered batteries more affordable for consumers.
III. Using solar-powered batteries will substantially reduce electricity costs and environmental impact.
A.Only I and II are implicit
B.Only II and III are implicit
C.All are implicit
D.Only I is implicit
Solution
Statement — assumptions
The statement links 'more expensive' with the need for incentives — so price is assumed to be the obstacle: I is implicit.
Calling incentives 'necessary to encourage use' assumes they will make the batteries affordable: II is implicit.
III (big cuts in bills and pollution) is nowhere assumed in the statement.
Hence Only I and II — option (a).
11
Statement:
The city public library is open from 10 AM to 6 PM.
Conclusions:
I. Visitors can borrow books after 6 PM.
II. The library is not accessible before 10 AM.
A.Only Conclusion I follows
B.Only Conclusion II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Statement — conclusions
Open 10 AM – 6 PM means closed outside these hours.
So borrowing after 6 PM is NOT possible — I does not follow.
Before 10 AM it is closed, i.e. not accessible — II follows.
Hence Only II — option (b).
12
Each of the letters in the word FORMATION is arranged in alphabetical order. How many letters are there in the English alphabetical series between the letter that is third from the left and the one that is fourth from the right in the new letter-cluster formed?
A.5
B.6
C.7
D.8
Solution
Alphabetical arrangement — FORMATION
FORMATION sorted: A, F, I, M, N, O, O, R, T (9 letters).
Third from left = I; fourth from right = 6th letter = O.
Between I and O in the alphabet: J, K, L, M, N.
Count = 5 — option (a).
13
Choose the correct option to complete the series.
Illuminate : Darken :: Encourage : ?
A.Cheer
B.discouraged
C.Support
D.Praise
Solution
Antonym analogy
Illuminate and Darken are opposites.
So we need the opposite of Encourage.
That is discourage(d); cheer, support and praise are synonyms.
Hence option (b).
14
Apply the same pattern to the third word and find the correct answer from the given alternatives.
AGOW : BHPX :: CIQY : ?
A.DJRX
B.DJRZ
C.DJRY
D.DRYJ
Solution
Coding (+1)
AGOW → BHPX: A+1 = B, G+1 = H, O+1 = P, W+1 = X — every letter +1.
Apply to CIQY: C+1 = D, I+1 = J.
Q+1 = R, Y+1 = Z.
Hence DJRZ — option (b).
15
Find the person that does not fit in the series:
Jawaharlal Nehru, Atal Bihari Vajpayee, Manmohan Singh, Bhagat Singh, Indira Gandhi
A.Bhagat Singh
B.Jawaharlal Nehru
C.Atal Bihari Vajpayee
D.Indira Gandhi
Solution
Odd one — not a PM
Nehru, Vajpayee, Manmohan Singh and Indira Gandhi all served as PRIME MINISTERS of India.
Bhagat Singh was a revolutionary freedom fighter, never a Prime Minister.
He breaks the category.
Hence option (a).
16
Determine the logic and find the missing value.
FM : :: HP : ?
A.
B.
C.
D.
Solution
Squares of place values
F = 6, M = 13 ⇒ 6² = 36 over 13² = 169 ✓.
So the fraction is (1st letter)² / (2nd letter)².
H = 8, P = 16 ⇒ 8² / 16².
= — option (b).
17
Arrange the following words in dictionary order and choose the second word:
stare, stack, stamp, stage
A.stage
B.stack
C.stamp
D.stare
Solution
Dictionary order
All start with 'sta'; compare the 4th letter: stack(c), stage(g), stamp(m), stare(r).
Order: stack, stage, stamp, stare.
The second word is stage.
Hence option (a).
18
In a certain code, MARKET is written as NYRLCT. Using the same pattern, how is FOLDER written?
A.GMLECR
B.MGLERC
C.GMECRL
D.GMLERC
Solution
Coding (+1, −2, 0)
MARKET → NYRLCT: M+1 = N, A−2 = Y, R+0 = R, K+1 = L, E−2 = C, T+0 = T.
Pattern by position: +1, −2, 0, +1, −2, 0.
FOLDER: F+1 = G, O−2 = M, L = L, D+1 = E, E−2 = C, R = R.
Hence GMLECR — option (a).
19
Find the odd one out from the given alternatives:
A.Mohiniyattam
B.Kuchipudi
C.Manipuri
D.Bhangra
Solution
Classical vs folk dance
Mohiniyattam (Kerala), Kuchipudi (Andhra) and Manipuri (Manipur) are CLASSICAL dances.
Bhangra is a FOLK dance of Punjab.
It belongs to a different category.
Hence option (d).
20
In a certain code language, Greek letters are used to represent English letters in a consistent manner. Based on the given coded words, determine the correct English decoding of the target sequence using the same letter-to-letter substitution pattern.
If 'γϕψβϕα' is coded as 'CAUGHT', 'σφςξσ' is coded as 'EAGLE', then what does 'σασψςσ' represent?
A.ETEUGE
B.ETEUUE
C.EEEUGE
D.ETEUGG
Solution
Symbol substitution code
Match symbols position by position. From EAGLE = σφςξσ: σ = E, ς = G.
From CAUGHT = γϕψβϕα: ψ = U, α = T.
Now read σασψςσ: E T E U G E.
Hence ETEUGE — option (a).
21
If 5 ∗ 3 = 40, 4 ∗ 2 = 24, then what is 6 ∗ 3?
A.48
B.60
C.54
D.42
Solution
Number puzzle ((a+b)×a)
Rule: a ∗ b = (a + b) × a.
Check: (5+3)×5 = 40 ✓; (4+2)×4 = 24 ✓.
6 ∗ 3 = (6+3)×6 = 54.
Hence option (c).
22
What is the value of Middle if Left = 8, Right = 14 and Middle is the average of both?
A.15
B.11
C.16
D.20
Solution
Average of two
Middle = .
= = .
= 11.
Hence option (b).
23
If '+' means 'divided by', '−' means 'multiplied by', '×' means 'minus', and '÷' means 'plus', find the value of: 36×6÷9+3−5 = ?
If P denotes '+', Q denotes '−', R denotes '×', and S denotes '÷', then what will come in place of '?' in the following equation?
120 P 30 S 6 R ? = 150
In a zoo, there are only Peacocks and Deers. Total heads = 40, and total legs = 100. How many Peacocks are there?
A.20
B.25
C.30
D.35
Solution
Heads and legs
Let peacocks = x, deer = y: x + y = 40 and 2x + 4y = 100.
Halve the second: x + 2y = 50.
Subtract: y = 10, so x = 30.
Hence 30 peacocks — option (c).
Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
Number the words: Software(1) development(2) is(3) progressing(4) very(5) quickly(6).
The last word is quickly (6th).
The 2nd last is the 5th word — very.
Hence option (c).
These are consecutive letters of the Greek alphabet.
Order: … Eta (7th), Theta (8th), Iota (9th), Kappa (10th) …
The 11th Greek letter is Lambda (then Mu, Nu, Xi).
Hence option (c).
The 15 letters split into three blocks of 5: qr_tu / _rs_u / q_stu.
Each block is the word qrstu repeated.
Blanks in order: s, q, t, r.
Hence option (a).
X's mother's husband is X's father.
His ONLY son is Y — so X, being his child but not Y, cannot be a son.
X must be a daughter — Y’s sister.
Hence option (a).
X is the mother and Z is the father of the same child Y.
So X and Z are the parents — a married couple.
Z is X’s husband.
Hence option (a).
Recognise the pattern nⁿ: 1¹, 2², 3³, 4⁴, 5⁵.
1, 4, 27, 256, 3125 ✓.
Next: 6⁶ = 46656.
Hence option (c).
Each term is roughly double the previous: 6 → 14 → 30 → 62 → 128.
The last step 62 → 128 and the sequence keep doubling.
128 × 2 = 256.
Hence option (d).
Rule: a @ b = (a + b) × 2.
(5+2)×2 = 14 ✓, (6+3)×2 = 18 ✓, (4+4)×2 = 16 ✓.
(7+3)×2 = 20, not 22.
Hence option (b) is the odd one.
FORMATION sorted: A, F, I, M, N, O, O, R, T (9 letters).
Third from left = I; fourth from right = 6th letter = O.
Between I and O in the alphabet: J, K, L, M, N.
Count = 5 — option (a).
AGOW → BHPX: A+1 = B, G+1 = H, O+1 = P, W+1 = X — every letter +1.
Apply to CIQY: C+1 = D, I+1 = J.
Q+1 = R, Y+1 = Z.
Hence DJRZ — option (b).
F = 6, M = 13 ⇒ 6² = 36 over 13² = 169 ✓.
So the fraction is (1st letter)² / (2nd letter)².
H = 8, P = 16 ⇒ 8² / 16².
= — option (b).
MARKET → NYRLCT: M+1 = N, A−2 = Y, R+0 = R, K+1 = L, E−2 = C, T+0 = T.
Pattern by position: +1, −2, 0, +1, −2, 0.
FOLDER: F+1 = G, O−2 = M, L = L, D+1 = E, E−2 = C, R = R.
Hence GMLECR — option (a).
Match symbols position by position. From EAGLE = σφςξσ: σ = E, ς = G.
From CAUGHT = γϕψβϕα: ψ = U, α = T.
Now read σασψςσ: E T E U G E.
Hence ETEUGE — option (a).
Rule: a ∗ b = (a + b) × a.
Check: (5+3)×5 = 40 ✓; (4+2)×4 = 24 ✓.
6 ∗ 3 = (6+3)×6 = 54.
Hence option (c).
Let peacocks = x, deer = y: x + y = 40 and 2x + 4y = 100.
Halve the second: x + 2y = 50.
Subtract: y = 10, so x = 30.
Hence 30 peacocks — option (c).