SSC CGL 21 September 2025 · Shift 1 · General Intelligence & Reasoning — questions with answers · ShikshaSphere
Chapter 109 of 192
21 September 2025 · Shift 1
General Intelligence & Reasoning
25 questions ~25 min readFree
25 questions
A
1
If in the word COMPUTER all vowels are removed, which letter will be the 3rd from the left?
A.M
B.P
C.T
D.R
Solution
Remove vowels
COMPUTER has the vowels O, U and E.
Removing them leaves C, M, P, T, R.
Counting from the left: C is 1st, M is 2nd, P is 3rd.
Hence P — option (b).
2
Choose the address that is the same as the one given below.
House No. 27A, Green Valley Road, Sector 8, Chandigarh - 160009
A.House No. 27, Green Valley Road, Sector 8, Chandigarh - 160009
B.House No. 27A, Green Valley Road, Sector 8, Chandigarh - 160009
D.House No. 27A, Green Valley Road, Sector 9, Chandigarh - 160009
Solution
Address matching
(a) drops the 'A' from 27A; (c) misspells 'Vally'.
(d) changes the sector to 9.
Only (b) matches the sample exactly.
Hence option (b).
3
Consider the following statement and choose the option that follows.Statement: The prices of petrol and diesel have increased sharply in the past few weeks.
Inferences:
I. People may start using public transport more frequently.
II. The government has decided to ban private vehicles.
A.Only I follows
B.Only II follows
C.Both follow
D.Neither follows
Solution
Statement — inferences
Costlier fuel makes private travel expensive, so a shift to buses and trains is a fair inference — I follows.
Nothing in the statement mentions any government ban.
A price rise does not imply a prohibition — II does not follow.
Hence Only I — option (a).
4
Replace the special characters with mathematical signs as given in the options to make a meaningful equation.
15 # 3 @ 5 = 50
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:
BIU, BMQ, BQM, BUI, ?
A.BYE
B.BXE
C.BYF
D.BZF
Solution
Letter series (+4, −4)
The 1st letter stays B throughout.
2nd letters: I, M, Q, U — each +4 ⇒ next is Y.
3rd letters: U, Q, M, I — each −4 ⇒ next is E.
Hence BYE — option (a).
6
What is the remainder when 876543210 is divided by 9?
A.0
B.1
C.2
D.3
Solution
Divisibility by 9
A number is divisible by 9 when its digit sum is a multiple of 9.
Digit sum = 8+7+6+5+4+3+2+1+0 = 36.
36 ÷ 9 = 4 exactly.
So the remainder is 0 — option (a).
7
Identify the correct pair of signs to interchange.
3 × 4 + 6 ÷ 2 − 5 = 10
A.+ and −
B.× and ÷
C.÷ and −
D.× and +
Solution
Interchange signs
Interchange × and + : the equation becomes 3 + 4 × 6 ÷ 2 − 5.
BODMAS: 4 × 6 = 24, then 24 ÷ 2 = 12.
3 + 12 − 5 = 10 ✓ — it matches the right-hand side.
Hence × and + — option (d).
8
Identify the pattern:
555 × 444, 444 × 333, 333 × 222, ____
Which fits next?
A.111 × 222
B.222 × 111
C.222 × 333
D.333 × 444
Solution
Descending triplets
In each pair the first number drops by 111 and so does the second.
555, 444, 333 → next first number is 222.
444, 333, 222 → next second number is 111.
Hence 222 × 111 — option (b).
9
Identify the word that is different.
A.Ganga
B.Yamuna
C.Bay of Bengal
D.Godavari
Solution
Rivers vs sea
Ganga, Yamuna and Godavari are all RIVERS.
The Bay of Bengal is a sea — a large body of salt water.
So it belongs to a different category.
Hence option (c).
10
Choose the odd one out.
A.Wing
B.Beak
C.Eye
D.Heart
Solution
External vs internal organ
Wing, beak and eye are all EXTERNAL body parts that can be seen.
The heart is an internal organ.
So it differs from the rest.
Hence option (d).
11
P is Q's father. R is Q's sister. S is P's wife. How is S related to R?
A.Mother
B.Grandmother
C.Aunt
D.Cousin
Solution
Blood relation
P is the father of Q, and R is Q’s sister, so R is also P’s child.
S is P’s wife, hence the mother of their children.
So S is R’s mother.
Hence option (a).
12
If P is the father of Q, but Q is not the son of P, then how is Q related to P?
A.Sister
B.Mother
C.Cousin
D.Daughter
Solution
Blood relation
P is Q’s father, so Q is P’s child.
Since Q is not the son, Q must be female.
A female child is a daughter.
Hence option (d).
13
Find the missing number in the series:
3, 9, 27, ?, 243, 729
A.81
B.64
C.121
D.100
Solution
Powers of 3
These are successive powers of 3: 3¹, 3², 3³, …
After 27 = 3³ comes 3⁴.
3 × 27 = 81 (and 81 × 3 = 243 ✓).
Hence option (a).
14
A conflict arises between two team members. What should you do as a team leader?
A.Ignore the issue
B.Take sides with one member
C.Listen to both and resolve the issue fairly
D.Complain to higher management
Solution
Ethics — team conflict
A leader is expected to keep the team working together.
Hearing both sides and settling the matter fairly restores trust.
Ignoring it lets the rift grow; taking sides or escalating at once is unfair.
Hence option (c).
15
If 1 = 1, 2 = 8, 3 = 27, 4 = 64 and 5 = 125, then 6 = ?
A.156
B.196
C.216
D.256
Solution
Cubes
Rule: each number equals its own cube, n = n³.
Check: 2³ = 8 ✓, 3³ = 27 ✓, 5³ = 125 ✓.
6³ = 6 × 6 × 6.
= 216 — option (c).
16
Study the following information and answer the question.
Eight persons — Ramesh, Jai, Shyam, Nidhi, Ram, Rahul, Suresh and Amit — live on eight different floors of an 8-storey building; the ground floor is numbered 1 and the top floor 8.
Rahul lives on an even numbered floor but not on the 6th floor. Amit lives below Shyam's floor. Ram lives two floors above Jai's floor. Ramesh lives on an even numbered floor but not adjacent to Ram's floor. Rahul lives just above Suresh's floor. Shyam lives on the 3rd floor. Ram does not live on the topmost floor. Nidhi's floor is not adjacent to Jai's floor.
How many persons live between Rahul's and Jai's floor?
A.Three
B.Five
C.Four
D.Six
Solution
Floor puzzle
Shyam is on 3 and Amit below him, so Amit takes floor 1. Ram is two above Jai and not on 8.
Jai on 2 and Ram on 4 fits; Rahul is on an even floor (not 6) just above Suresh, so Rahul 8 and Suresh 7.
Ramesh must be on an even floor not next to Ram(4), so Ramesh 6, leaving 5 for Nidhi — her floor is not adjacent to Jai(2) ✓.
Between Rahul(8) and Jai(2) lie floors 3-7 = five persons — option (b).
17
These questions are based on the following information.
There are 7 family members: A, B, C, D, E, F and G going to a party. There are three generations, in which only two are married couples. A is the grandfather of F, who is a male. C is the son-in-law of D. G is the son of B. D has only two children, both of the same gender. E is the sister-in-law of C.
How many males are there?
A.4
B.5
C.3
D.2
Solution
Family — number of males
A is a grandfather, so A is male; F is stated to be male; G is a son, so male.
C is a son-in-law, hence male as well.
B, D and E are the remaining members and come out female.
So there are 4 males — option (a).
18
Read the following statements carefully and identify the conclusion that follows.Statements:
All teachers are educated.
Some educated are doctors.
All doctors are respected.
Conclusions:
I. Some teachers are respected.
II. Some educated are respected.
A.Only I follows
B.Only II follows
C.Both I and II follow
D.Neither I nor II follows
Solution
Syllogism
Some educated are doctors and all doctors are respected, so those educated persons are respected — II follows.
Teachers lie inside the educated group, but nothing places them in the doctor part of it.
So I is not certain.
Hence Only II — option (b).
19
The letters given below, when arranged, form a meaningful word:
NTAEPLEH
What is the position of the letter L in the word formed, counting from the left?
A.3
B.4
C.2
D.7
Solution
Jumbled word — ELEPHANT
The letters N, T, A, E, P, L, E, H rearrange to ELEPHANT.
Writing it out: E (1), L (2), E (3), P (4), H (5), A (6), N (7), T (8).
So L stands second from the left.
Hence option (c).
20
What comes next in the series?
B, E, H, K, ?
A.M
B.N
C.O
D.P
Solution
Letter series (+3)
Each letter moves three places forward.
B(2) → E(5) → H(8) → K(11).
11 + 3 = 14, which is N.
Hence option (b).
21
What comes next?
EG, GI, IK, ?
A.KN
B.JN
C.JM
D.KM
Solution
Letter series (+2)
Within each pair the two letters differ by 2.
1st letters: E, G, I — each +2 ⇒ next is K.
2nd letters: G, I, K — each +2 ⇒ next is M.
Hence KM — option (d).
22
If '×' = '+', '+' = '−' and '−' = '×', then which of the following equations is correct?
In a room of 8 people, how many different handshakes are possible if each person shakes hands once with every other?
A.32
B.30
C.28
D.26
Solution
Handshakes
Each handshake involves a pair, so we count pairs.
Number = = .
= .
= 28 — option (c).
25
If TRAIN is coded as USBJO, how is USBJO coded?
A.VTCKP
B.VTCJP
C.UTCJP
D.VTCJO
Solution
Coding (+1)
Every letter moves +1: T+1 = U, R+1 = S, A+1 = B, I+1 = J, N+1 = O.
Apply the same rule again to USBJO: U+1 = V, S+1 = T, B+1 = C.
J+1 = K, O+1 = P.
Hence VTCKP — option (a).
Finished reading? Now test yourself.
The same 25 questions, but with a timer and the answers hidden — 15 minutes.
COMPUTER has the vowels O, U and E.
Removing them leaves C, M, P, T, R.
Counting from the left: C is 1st, M is 2nd, P is 3rd.
Hence P — option (b).
Test option (a): 15 × 3 + 5.
15 × 3 = 45.
45 + 5 = 50 = RHS ✓.
Hence × and + — option (a).
The 1st letter stays B throughout.
2nd letters: I, M, Q, U — each +4 ⇒ next is Y.
3rd letters: U, Q, M, I — each −4 ⇒ next is E.
Hence BYE — option (a).
A number is divisible by 9 when its digit sum is a multiple of 9.
Digit sum = 8+7+6+5+4+3+2+1+0 = 36.
36 ÷ 9 = 4 exactly.
So the remainder is 0 — option (a).
Interchange × and + : the equation becomes 3 + 4 × 6 ÷ 2 − 5.
BODMAS: 4 × 6 = 24, then 24 ÷ 2 = 12.
3 + 12 − 5 = 10 ✓ — it matches the right-hand side.
Hence × and + — option (d).
In each pair the first number drops by 111 and so does the second.
555, 444, 333 → next first number is 222.
444, 333, 222 → next second number is 111.
Hence 222 × 111 — option (b).
P is the father of Q, and R is Q’s sister, so R is also P’s child.
S is P’s wife, hence the mother of their children.
So S is R’s mother.
Hence option (a).
P is Q’s father, so Q is P’s child.
Since Q is not the son, Q must be female.
A female child is a daughter.
Hence option (d).
These are successive powers of 3: 3¹, 3², 3³, …
After 27 = 3³ comes 3⁴.
3 × 27 = 81 (and 81 × 3 = 243 ✓).
Hence option (a).
Rule: each number equals its own cube, n = n³.
Check: 2³ = 8 ✓, 3³ = 27 ✓, 5³ = 125 ✓.
6³ = 6 × 6 × 6.
= 216 — option (c).
Shyam is on 3 and Amit below him, so Amit takes floor 1. Ram is two above Jai and not on 8.
Jai on 2 and Ram on 4 fits; Rahul is on an even floor (not 6) just above Suresh, so Rahul 8 and Suresh 7.
Ramesh must be on an even floor not next to Ram(4), so Ramesh 6, leaving 5 for Nidhi — her floor is not adjacent to Jai(2) ✓.
Between Rahul(8) and Jai(2) lie floors 3-7 = five persons — option (b).
Some educated are doctors and all doctors are respected, so those educated persons are respected — II follows.
Teachers lie inside the educated group, but nothing places them in the doctor part of it.
So I is not certain.
Hence Only II — option (b).
The letters N, T, A, E, P, L, E, H rearrange to ELEPHANT.
Writing it out: E (1), L (2), E (3), P (4), H (5), A (6), N (7), T (8).
So L stands second from the left.
Hence option (c).
Each letter moves three places forward.
B(2) → E(5) → H(8) → K(11).
11 + 3 = 14, which is N.
Hence option (b).
Within each pair the two letters differ by 2.
1st letters: E, G, I — each +2 ⇒ next is K.
2nd letters: G, I, K — each +2 ⇒ next is M.
Hence KM — option (d).
Test option (c): 10 × 2 − 6 + 4 becomes 10 + 2 × 6 − 4.
BODMAS: 2 × 6 = 12.
10 + 12 − 4 = 18 = RHS ✓.
Hence option (c).
Each term = previous × 2 + 1.
3×2+1 = 7, 7×2+1 = 15, 15×2+1 = 31, 31×2+1 = 63 ✓.
Next: 63 × 2 + 1 = 126 + 1.
= 127 — option (c).
Each handshake involves a pair, so we count pairs.
Number = = .
= .
= 28 — option (c).
Every letter moves +1: T+1 = U, R+1 = S, A+1 = B, I+1 = J, N+1 = O.
Apply the same rule again to USBJO: U+1 = V, S+1 = T, B+1 = C.
J+1 = K, O+1 = P.
Hence VTCKP — option (a).