29 November 2025 · Shift 1

Number series The terms grow very fast, so test a multiply-and-add rule rather than a difference rule. $7\times 3+1=22$, $22\times 3+1=67$ and $67\times 3+1=202$, so each term is 3 times the previous term plus 1. Therefore the next term $=202\times 3+1=606+1=607$. Hence the correct option is (a).

Ranking in a queue Ravi stands ahead of Mohit, so the queue breaks into three parts that do not overlap at all. Ravi together with everyone in front of him makes 12 persons. Next come the 4 persons standing between Ravi and Mohit. Mohit together with everyone behind him makes 14 persons. Total number of persons =12+4+14=30. Hence the correct option is (a).

Ranking in a row Manoj stands ahead of Amit, so Manoj's place from the front is the smaller of the two. Amit is 11th from the front and 5 persons stand between them, so Manoj is 11-5-1=5th from the front. Manoj is also 17th from the back. For one person counted from both ends, total = place from front + place from back -1. Total =5+17-1=21. Hence the correct option is (a).

Number operation rule In each set the third number is much smaller than the first, so try the difference of the two numbers divided by a constant. $\left(124-25\right)÷3=\frac{99}{3}=33$, which is the given result. $\left(121-61\right)÷3=\frac{60}{3}=20$, which is again the given result, so the rule is confirmed. Applying it, the required value $=\left(172-46\right)÷3=\frac{126}{3}=42$. Hence the correct option is (a).

Number operation rule Here the result is far larger than the two numbers, so test a product rule. $19\times 27=513$ and $513\times 6=3078$, the given result. $38\times 49=1862$ and $1862\times 6=11172$, again the given result, so the rule is: multiply the two numbers and then multiply by 6. Applying it, the required value $=3\times 50\times 6=150\times 6=900$. Hence the correct option is (b).

Number series on cubes Each term lies just below the cube of a natural number, so compare the series with consecutive cubes. ${11}^3=1331$ and 1331-10=1321; ${12}^3=1728$ and 1728-10=1718. ${13}^3=2197$ and 2197-10=2187; ${14}^3=2744$ and 2744-10=2734. So the nth term is (cube) -10, and the next term $={15}^3-10=3375-10=3365$. Hence the correct option is (d).

Paper folding and punching The sheet is folded twice — the lower half up and then the right half onto the left — so the punches are made on the quarter lying at the top-left. Two folds give $2^2=4$ layers, so each punch cuts 4 holes and the three punches open into $4\times 3=12$ holes: eight square and four round. Undoing the vertical fold reflects the punched quarter in the vertical centre line and fills the whole upper half. Undoing the horizontal fold reflects that upper half in the horizontal centre line, so the lower half repeats the same pattern turned upside down. The top and the bottom rows therefore carry two square holes each, while the two middle rows read square, circle, circle, square from left to right. Only option (c) shows this arrangement, so option (c) is correct.

Paper folding and punching The sheet is folded three times — the lower half up, then the right half onto the left, and then the right half onto the left once more. Three folds give $2^3=8$ layers, so each of the two punches cuts 8 holes and the opened sheet carries $2\times 8=16$ marks. Undoing the two vertical folds spreads the punched pair sideways into four identical columns, and a left-right flip never changes which mark lies above the other. On the folded strip the wide mark is above the tall mark, so every column of the upper half keeps that order. Undoing the horizontal fold prints the upper half into the lower half as a mirror image, so there the tall mark comes above the wide mark. Only option (c) shows four such columns in both halves, so option (c) is correct.

Number series Take the differences of consecutive terms: 21-12=9, 32-21=11, 45-32=13, 60-45=15. The differences are consecutive odd numbers, so the next difference is 17. Therefore the next term =60+17=77. The same series can be read as $n^2-4$: $4^2-4=12$, $5^2-4=21$, $\dots$, $9^2-4=77$. Hence the correct option is (a).

Number puzzle in boxes Read every box as a $2\times 2$ grid and look for a rule that binds the four numbers. The rule is: (top-right number $\times$ bottom-left number) + top-left number = bottom-right number. First box: $4\times 3+5=12+5=17$. Second box: $5\times 2+6=10+6=16$. Third box: $?\times 3+4=19$, so $?\times 3=15$ and ?=5. Hence the correct option is (c).

Counting triangles Name the points: the rectangle is ABCD, the two apexes are P (top) and Q (bottom), E and F are the mid-points of AB and DC, G,H and I,J are the other cuts on AB and DC, and K,L are the crossings inside the left and the right halves. Triangles having P as a vertex: PGE, PEH, PGH, PDF, PFC, PDC, PQK, PQL — that is 8. Triangles having Q as a vertex but not P: QIF, QFJ, QIJ, QAE, QEB, QAB — that is 6 more. In the left half the side AD and the crossing K give ADG, ADI, ADK, AGK, DIK — that is 5. The right half is its mirror image and gives BCH, BCJ, BCL, BHL, CJL — another 5. Total =8+6+5+5=24. Hence the correct option is (b).

Venn diagram counting Balls that are only tables means the region common to the rectangle and the circle but lying outside the triangle, and that region carries 10. So statement I is correct. Total bats = all four parts of the triangle =11+8+7+12=38. Total balls = all four parts of the rectangle =13+10+8+11=42. The bats fall short of the balls by 42-38=4, not by 14, so statement II is wrong. Hence the correct option is (a).

Circular seating All five face the centre, so for each of them the right hand points in the anticlockwise direction. Fix S; moving two seats anticlockwise places Q, and two more anticlockwise seats place P. Only two seats are now empty — the one immediately anticlockwise of S and the one lying between Q and P. R must not sit next to P, so R takes the seat anticlockwise of S and T takes the remaining seat. Counting anticlockwise from S we get R, Q, T, so T is third to the right of S. Hence the correct option is (c).

Ranking in a row B is the 8th person from the left end. Five persons stand between B and Y, so Y is either the 8+5+1=14th or the 8-5-1=2nd person from the left. If Y were 2nd from the left, he would already be second from that end and the row could be of any length, so this case fixes nothing. Hence Y is 14th from the left and is the second person from the right end. One person stands to the right of Y, so the total =14+1=15. Hence the correct option is (a).

Figure analogy In the first pair the inner polygon loses one side: a hexagon of 6 sides becomes a pentagon of 5 sides. At the same time the letter inside is turned through ${180}^{\circ }$ — the upside-down K becomes an upright K. The third figure carries an octagon of 8 sides with an upside-down P inside it. Applying the same rule, the missing figure must be a heptagon of 8-1=7 sides carrying an upright P. Only option (b) shows a seven-sided figure with the letter P the right way up, so option (b) is correct.

Figure analogy — mirror Compare the first two figures: the second is the first turned upside down, that is, reflected in a horizontal line. The dot that sat at the upper end of the slanting line comes to the lower end, the diamond that sat at the lower end goes to the upper end, and the shaded half of the circle moves from below the slanting line to above it. The same reflection has to be applied to the third figure, so the upright triangle becomes an inverted triangle. The dot on the top vertex therefore comes to the bottom vertex, the stem carrying the second dot turns upward and sticks out above the horizontal side, and the group of parallel lines stays at the same distance from that horizontal side. The figure in option (b) is exactly this reflection. Hence the correct option is (b).

Figure series In every figure five small shapes lie one after another along the diagonal that runs from the top-left corner to the bottom-right corner. From one figure to the next the whole chain slides one place down this diagonal; the shape pushed off the lower end is parked in the top-right corner of the next figure and a fresh shape enters at the top-left end. So the chain circle, square, diamond, five-pointed star, arrow of the first figure becomes four-pointed star, circle, square, diamond, five-pointed star in the second, with the arrow in the corner. In the fourth figure the chain is triangle, bar, four-pointed star, circle, square and the diamond stands in the corner. The fifth figure must therefore carry triangle, bar, four-pointed star, circle in its last four diagonal places, a new shape at the top-left end, and the square in the top-right corner. Hence the correct option is (d).

Interchange of signs The two signs that change places are - and $÷$, so every - in the equation becomes $÷$ and every $÷$ becomes -. $40+20\times 15-5÷5$ therefore becomes $40+20\times 15÷5-5$. By BODMAS, multiplication and division are done first, working from left to right: $20\times 15÷5=300÷5=60$. The expression is now 40+60-5=95. Hence the correct option is (d).

Balancing an equation Four signs are needed, one for each $*$ in $24*4*30*6*7=94$. Put the signs $\times ,+,÷,-$ in that order: $24\times 4+30÷6-7$. By BODMAS the division and the multiplication come first: $24\times 4=96$ and $30÷6=5$. So the left side becomes 96+5-7=94, which is the value required on the right side. Hence the correct option is (a).

Letter-number odd one out Check the letters first: in every pair the first letter moves one step back and the second letter moves two steps back, as in $T\to S$ and $B\to Z$. So the letters are the same in all four pairs and cannot decide the answer; the numbers must. Taking each number as a whole number, 287+294=581, 231+294=525 and 410+294=704, so the rule is 'add 294'. In QL320 – PJ604, however, 320+294=614, not 604, so this pair does not follow the rule. Hence the correct option is (b).

Letter-number odd one out In the first three pairs the first letter moves three steps back and the second letter six steps back, counting backwards through the alphabet: $R\to O$, $C\to W$ (C, B, A, Z, Y, X, W). The number of each pair is three times the first number, decreased by 1. Thus $206\times 3-1=617$, $194\times 3-1=581$ and $187\times 3-1=560$, all of which agree with the pairs shown. In ER313 – BN939 the letter shift is $E\to B$ (-3) but $R\to N$ is only -4 instead of -6, and the number gives $313\times 3-1=938$, not 939. Hence the correct option is (d).

Number pair odd one out Compare the two numbers of each pair without breaking them into digits: the first number looks like four times the second. $2652÷4=663$, $1548÷4=387$ and $2376÷4=594$, so these three pairs obey the rule 'second number = first number $÷4$'. For the last pair $1981÷4=495.25$, which is not 492, so 1981 – 492 is the odd pair. Hence the correct option is (d).

Odd group of numbers In each group compare the second and the third number with the first one. The second number is twice the first and the third number is two and a half times the first, so the three numbers stand in the ratio 2:4:5. $48\times 2=96$ and $48\times 2.5=120$; $90\times 2=180$ and $90\times 2.5=225$; $72\times 2=144$ and $72\times 2.5=180$. For (66, 132, 170) the doubling is right, but $66\times 2.5=165$, so the third number should be 165 and not 170. Hence the correct option is (b).

Letter-number analogy Take the letters first: the first letter moves one step back and the second letter one step forward, as in $B\to A$, $M\to N$ and $C\to B$, $S\to T$. Now the numbers, kept whole: 112+450=562 and 280+450=730, so 450 is added every time. For GX96 the letters give $G\to F$ and $X\to Y$, that is FY. The number gives 96+450=546, so the required cluster is FY546. Hence the correct option is (c).

Letter-number analogy Letters first: both letters of the cluster move six steps back — $P\to J$, $Q\to K$ and $G\to A$, $O\to I$. Now the numbers, kept whole: $8^2+2=64+2=66$ and ${19}^2+2=361+2=363$, so the number is squared and 2 is added. For BX13 the letters give $B\to V$ and $X\to R$, that is VR. The number gives ${13}^2+2=169+2=171$, so the required cluster is VR171. Hence the correct option is (d).